Question

acetylene gas c2h2 undergoes combustion to produce carbon dioxide and water vapor How many grams of water are produced by the same amount of C2H2?

Answer 1

Answer: The amount of water produced in the given reaction is $0.692x$ grams.

Explanation:

Let us assume that the initial amount of acetylene gas given be 'x' grams. Now, to calculate the number of moles, we will use the formula:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$   ....(1)

Given mass of acetylene = x grams

Molar mass of acetylene = 26 g/mol

Putting values in above equation, we get:

$\text{Number of moles of acetylene}=\frac{xg}{26g/mol}=\frac{x}{26}mol$

The reaction of combustion of acetylene is given by the equation:

$2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O$

By Stoichiometry of the reaction:

2 moles of acetylene produces 2 moles of water.

So, $\frac{x}{26}$ moles of acetylene will produce = $\frac{2}{2}\times \frac{x}{26}=\frac{x}{26}$ moles of water.

Now, to calculate the amount of water produced, we use equation 1:

Molar mass of water = 18 g/mol

Moles of water = $\frac{x}{26}mol$

Putting values in equation 1, we get:

$\frac{x}{26}mol=\frac{\text{Mass of water}}{18g/mol}$

$\text{Mass of water}=\frac{x}{26}\times 18=0.692x$ grams