The answer is negative 21
Answer:
On the surface, it seems easy. Can you think of the integers for x, y, and z so that x³+y³+z³=8? Sure. One answer is x = 1, y = -1, and z = 2. But what about the integers for x, y, and z so that x³+y³+z³=42?
That turned out to be much harder—as in, no one was able to solve for those integers for 65 years until a supercomputer finally came up with the solution to 42. (For the record: x = -80538738812075974, y = 80435758145817515, and z = 12602123297335631. Obviously.)
Step-by-step explanation:
Answer:
c) (x + 2)(x + 2i)(x - 2i)
Step-by-step explanation:
x^3 + 2x^2 + 4x + 8
= (x^3 + 2x^2) + (4x + 8)
= x^2( x + 2) + 4(x + 2)
= (x + 2)(x^2 + 4)
= (x + 2)(x^2 - 4i^2) ---------------------------->(i^2 = -1)
= (x + 2)(x + 2i)(x - 2i)
5 7/8 is 47/8
Because,
You multiply 5 and 8 and then add 7, then you keep the denominator.