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Mrac [35]
3 years ago
13

What is the sum of 1/4 and 3/8

Mathematics
1 answer:
kupik [55]3 years ago
4 0
\dfrac{1}{4}+\dfrac{3}{8}=(*)\\Find\ LCD\ (Least\ Common\ Denominator)\\list\ the\ multiples\\of\ 4:\ \ 0;\ 4;\ \fbox8;\ 12;...\\of\ 8:\ \ 0;\ \fbox8;\ 16;\ 24;\ ...\\LCD\left(\dfrac{1}{4};\ \dfrac{3}{8}\right)=8\\\\(*)=\dfrac{1\cdot2}{4\cdot2}+\dfrac{3}{8}=\dfrac{2}{8}+\dfrac{3}{8}=\dfrac{2+3}{8}=\dfrac{5}{8}
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Answer:

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Step-by-step explanation:

Cube root of 175616 by prime factorization method is 56

Solution:

To find cube root of 175616 by prime factorization method

A number that must be multiplied by itself three times to equal a given number is called cube root

Prime factorization method:

Prime factorization is a number written as the product of all its prime factors.

In order of finding cube root by prime factorization we use the following steps:

Step I : Obtain the given number

Step II : Resolve it into prime factors.

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Prime factorization of 175616:

\text{ prime factors of 175616 } = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 7 \times 7 \times 7 prime factors of 175616 =2×2×2×2×2×2×2×2×2×7×7×7

Thus we get,

\sqrt[3]{175616} = \sqrt[3]{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 7 \times 7 \times 7}

3

175616

=

3

2×2×2×2×2×2×2×2×2×7×7×7

Make the groups of 3 of equal numbers

\sqrt[3]{175616} = \sqrt[3]{2 \times 2 \times 2} \times \sqrt[3]{2 \times 2 \times 2 \times } \times \sqrt[3]{2 \times 2 \times 2} \times \sqrt[3]{7 \times 7 \times 7}

3

175616

=

3

2×2×2

×

3

2×2×2×

×

3

2×2×2

×

3

7×7×7

So there are 4 equal groups. So from that group take one factor out

\sqrt[3]{175616} = 2 \times 2 \times 2 \times 7 = 56

3

175616

=2×2×2×7=56

Thus Cube root of 175616 by prime factorization method is 56

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