Let t=number of years since 1991.
Then
P(t)=147 e^(kt) ... in millions
P(0)=147 e^(0)=147
P(7)=147 e^(7k)=153
e^(7k)=(153/147)
take ln both sides
ln(e^(7k))=ln(153/147)
7k=0.0400 => k=0.005715
Year 2017=>t=2017-1991=26
P(26)=147e^(26*.005715)=170.55
Answer: in 2017, the projected population is 170.55 millions.
Answer:
For statement 1 :
INPUT UNIT OF ITEM : <em>Time of the year on Serengeti Desert</em>
OUTPUT UNIT OF ITEM : <em>Simba washes his clothes</em>
For statement 2
INPUT UNIT OF ITEM : <em>1 capful of detergent</em>
OUTPUT UNIT OF ITEM : <em>each load of wash</em>
Step-by-step explanation:
For statement 1 :
INPUT UNIT OF ITEM : <em>Time of the year on Serengeti Desert</em>
OUTPUT UNIT OF ITEM : <em>Simba washes his clothes</em>
For statement 2
INPUT UNIT OF ITEM : <em>1 capful of detergent</em>
OUTPUT UNIT OF ITEM : <em>each load of wash</em>
From answers provided above the basis for the answers is that an input unit of item will have to result to a reaction which is an output unit of item hence the answers above
Square root of 121 is 11.
11-7=4
A side of the original square is 4 feet.
Answer:
The claim that he rate of inaccurate orders is equal to 10% is supported by statistical evidnece at 5% level
Step-by-step explanation:
Given that in a study of the accuracy of fast food drive-through orders, one restaurant had 34 orders that were not accurate among 371 orders observed.
Sample proportion 

(Two tailed test at 5% significance level)
p difference = 
Std error if H0 is true = 
Test statistic Z = p diff/std error
=0.539
p value = 0.5899
Since p > 0.05 accept null hypothesis
The claim that he rate of inaccurate orders is equal to 10% is supported by statistical evidnece at 5% level