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fiasKO [112]
2 years ago
13

At the district competition for 5th grade jump-roper of the year, the following number of jumps without stopping were recorded p

er student:
203,245,237,233,90,100,100,277,265,264,265,285,288,291,
291,290,300,224,200,257,290,279,266,288

What is the mean number of jumps, rounded to the nearest hundredth?
What is the median number of jumps?
Mathematics
1 answer:
deff fn [24]2 years ago
5 0
First, we arrange the data from least to greatest:
  90, 100, 100, 200, 203, 224, 233, 237, 245, 257, 264, 265, 265, 266, 277, 279, 285, 288, 288, 290, 290, 291, 291, 300

There are 24 data all in all. The mean is calculated by dividing by 24 the sum of all the data.
                        mean = (5828)/24242.83

The median of the number of jumps is the mean of the 12th and 13th term.
                          265 
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What is the volume of the composite figure with the dimensions shown in the 3 views? (Round to the nearest tenth)
givi [52]

Answer:

278.9 units^3 to the nearest tenth.

Step-by-step explanation:

This is a cylinder on the bottom . resting on the cylinder is a prism.

Volume of the cylinder = π r^2 h  where r = 1/2 * 7 = 3.5 and h = 6.

V = π * 3.5^2 * 6 = 230.907 units^3.

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Volume of the composite figure = 230.907 + 48

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6 0
2 years ago
What is the solution to the equation 37 x = 9 x + 4 ?<br> -7<br> − 1/7<br> 1/7<br> 7
natali 33 [55]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

let's solve for x ~

  • 37x =  9x + 4

  • 37x - 9x = 4

  • 28x = 4

  • x =  \dfrac{4}{28}

  • x =  \dfrac{1}{7}

5 0
2 years ago
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6 people equally share bill rs 98.10 how ​
AnnZ [28]

Answer:

16.35Rs would be paid by everyone.

Step-by-step explanation:

98.10/6

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3 0
2 years ago
Determine whether each piece of given information alone is sufficient to prove quadrilateral ABCD is parallelogram. Justify your
denis-greek [22]

Answer:

Yes it is parallelogram because diagonals bisect each other.

6 0
3 years ago
The sum of 5 consecutive integers is 265. What is the fifth number in this sequence ?
Yanka [14]
Hello,
Let's assume n,n+1,n+2,n+3,n+4 the 5 numbers

n+(n+1)+...+(n+4)=5n+10=265
5n=265-10
5n=255
n=51
The 5th number is 51+4=55

6 0
3 years ago
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