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poizon [28]
3 years ago
10

Which of the following is the most appropriate unit to describe the rate at which data is transferred using the internet?

Mathematics
2 answers:
NISA [10]3 years ago
4 0
Megabits per second, because the independent quality is time in seconds and dependent quality is amount of data in megabits.
sveticcg [70]3 years ago
3 0

The <em><u>correct answer</u></em> is:

Mbps, or megabits per second.

Explanation:

The standard measurement unit of data sent or received over the Internet is megabits per second.  This means "millions of bits per second."

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Figures are similar. Find x.
katrin [286]

Answer:

24.3

Step-by-step explanation:

18/20 = x/20 (similar triangles)

8 0
3 years ago
Which of the following best describes the slope of the line below?
strojnjashka [21]

Answer:

D. Undefined

Step-by-step explanation:

It is a vertical line so it has no slope.

5 0
3 years ago
Read 2 more answers
What was a effect on the war of 1812 <br>PLEASE HURRY AND HELP ME ​
labwork [276]

Answer:

The War of 1812 changed the course of American history. Because America had managed to fight the world's greatest military power to a virtual standstill, it gained international respect. Furthermore, it instilled a greater sense of nationalism among its citizens.

Step-by-step explanation:

8 0
2 years ago
Assume that you have a sample of n 1 equals 6​, with the sample mean Upper X overbar 1 equals 50​, and a sample standard deviati
tigry1 [53]

Answer:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

df=6+5-2=9

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

n_1 =6 represent the sample size for group 1

n_2 =5 represent the sample size for group 2

\bar X_1 =50 represent the sample mean for the group 1

\bar X_2 =38 represent the sample mean for the group 2

s_1=7 represent the sample standard deviation for group 1

s_2=8 represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 > \mu_2

We are assuming that the population variances for each group are the same

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic for this case is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

The pooled variance is:

S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

We can find the pooled variance:

S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67

And the pooled deviation is:

S_p=7.46

The statistic is given by:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

The degrees of freedom are given by:

df=6+5-2=9

The p value is given by:

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0
3 years ago
Find the volume of the prism.​
Gemiola [76]

Answer:

Step-by-step explanation:

The volume of the triangular prism, this is an isosceles triangular prism is

V=1/2 * a*b*h

V=1/2 x10x8x14=560 cm^3

4 0
2 years ago
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