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3 years ago

The multimeter read 0.0425 volts, 0.1582 volts and 0.0932 volts. Which is the highest reading on the multimeter?

Mathematics

1 answer:

vladimir1956 [14]3 years ago

6 0

Answer:

any number closest to 1 on the number line will be the highest reading.

.1582 is the highest number

Step-by-step explanation:

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Mr. Nelson sold 14 bags of popcorn and 21 bottles of water in today. At this rate, how many more bottles of water than bags of p

e-lub [12.9K]

Answer:

He will sell 70 bags of popcorn and 105 bottles

Step-by-step explanation:

In 1 day he sells 14 bags of popcorn and 21 bottles

Multiply 14 by 5 which is 70

then multiply the bottles which is 21 by 5 days

105

He will sell 70 bags of popcorn and 105 bottles

6 0

3 years ago

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Last week,the price of apples at a grocery store was 1.60 per pound.This week,apples at the same grocery store are on sale for a

Degger [83]

Answer:

The total price of $4\frac{1}{2}$ pounds of apples is $6.48.

Step-by-step explanation:

Given:

Last week,the price of apples at a grocery store was 1.60 per pound.This week,apples at the same grocery store are on sale for a 10% discount.

Now, to find the total price of 4 1/2 pounds of apples this week at the grocery store.

The price of apples at a grocery store last week was = $1.60 per pound.

This week apples at the same grocery store is on sale of 10% discount.

Thus, the price of apples at a grocery store this week is:

$1.60-10\%\ of\ 1.60.$

$=1.60-\frac{10}{100} \times 1.60$

$=1.60-0.16$

$=\$1.44.$

So, the price of apples per pound this week is $1.44.

Now, to get the total price of $4\frac{1}{2}$ pounds of apples by using unitary method:

If 1 pound of apples cost = $1.44.$

Then, $\frac{9}{2}$ pound of apples cost = $1.44\times \frac{9}{2}$

$=1.44\times 4.5$

$=\$6.48.$

Therefore, the total price of $4\frac{1}{2}$ pounds of apples is $6.48.

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3 years ago

Is something is less than 5 , do i include 5

notsponge [240]

Answer:

No.

Step-by-step explanation:

If something is less than 5, no, however if something is less than or equal to (≤ sign), then yes.

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2 years ago

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The nth term of the sequence is n+7 work out the tenth term of the sequence

worty [1.4K]

Answer:

Step-by-step explanation:

To obtain the tenth term, substitute n = 10 into the n th term formula, that is

n + 7 = 10 + 7 = 17 ← tenth term

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3 years ago

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If A is a 2 × 2 matrix, then A × I = and I × A =

krok68 [10]

Since the multiplication between two matrices is not commutative, then $\vec A\, \times\,\vec I \ne \vec I \,\times \,\vec A$ , regardless of the dimensions of $\vec A$ .

<h3>Is the product of two matrices commutative?</h3>

In linear algebra, we define the product of two matrices as follows:

$\vec C = \vec A \,\times \vec B$ , where $\vec A \in \mathbb{R}_{m\times p}$ , $\vec B \in \mathbb{R}_{p\times n}$ and $\vec C \in \mathbb{R}_{m \times n}$ (1)

Where each element of the matrix is equal to the following dot product:

$c_{ij} = \left[\begin{array}{cccc}a_{i1}&a_{i2}&\ldots&a_{ip}\end{array}\right]\,\bullet\,\left[\begin{array}{ccc}b_{1j}\\b_{2j}\\\vdots\\b_{pj}\end{array}\right]$ , where 1 ≤ i ≤ m and 1 ≤ j ≤ n. (2)

Because of (2), we can infer that the product of two matrices, no matter what dimensions each matrix may have, is not commutative because of the nature and characteristics of the definition itself, which implies operating on a row of the former matrix and a column of the latter matrix.

Such "arbitrariness" means that resulting value for $c_{ij}$ will be different if the order between $\vec A$ and $\vec B$ is changed and even the dimensions of $\vec C$ may be different. Therefore, the proposition is false.

To learn more on matrices: brainly.com/question/9967572

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2 years ago