1/4 is 0.25 as a fraction
To find the total probability, we first need to solve for the probability of the individual events.
Event 1:
P(consonant)=7/11
We know this to be true because out of the 11 total possibilities for the event, 7 of them are consonants.
R E P L A C E M E N T
Event 2
P(e)=3/10
We know this to be true because out of the 10 total possibilities for the event (since we didn't replace the first card we withdrew), 3 of them are the letter 'e'.
R E P L A C E M E N T (-1 to account for the first card we withdrew)
The possibility of both events...
P(consonant then 'e')=7/11*3/10=21/110
Answer: P=21/110
Answer:
Step-by-step explanation:
Remember:
![(\sqrt[n]{a})^n=a\\\\(a+b)=a^2+2ab+b^2](https://tex.z-dn.net/?f=%28%5Csqrt%5Bn%5D%7Ba%7D%29%5En%3Da%5C%5C%5C%5C%28a%2Bb%29%3Da%5E2%2B2ab%2Bb%5E2)
Given the equation 
, you need to solve for the variable "x" to find its value.
You need to square both sides of the equation:
Simplifying, you get:
Factor the quadratic equation. Find two numbers whose sum be 7 and whose product be -8. These are: -1 and 8:
Then:
Let's check if the first solution is correct:
(It checks)
Let's check if the second solution is correct:
(It does not checks)
Therefore, the solution is:
Answer:
b = (log(y^45))/log(1/y^9) + (2 i π n)/log(1/y^9) for n element Z
Step-by-step explanation:
Solve for b:
(1/y^9)^b = y^45
Take the logarithm base 1/y^9 of both sides:
Answer: b = (log(y^45))/log(1/y^9) + (2 i π n)/log(1/y^9) for n element Z
