For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3723

So $p = 0.3723$

12 games in November

So $n = 12$

What is the probability that the hockey team wins 6 games in November?

This is $P(X = 6)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{12,6}.(0.3723)^{6}.(1-0.3723)^{6} = 0.1505$

0.1505 = 15.05% probability that the hockey team wins 6 games in November

4 0

2 years ago

PLEASE HELP, SOLVE THIS PROBLEM AND GIVE ME THE ANSWER!!!

Elenna [48]

Answer:

11 is the answer

Step-by-step explanation: i hope so cuz my calculations gives this answer

5 0

2 years ago

There are 63 students in a speech contest.Yesterday 1/3 gave a speech and today 2/3 of the remaining students gave their speech.

Paraphin [41]

Hey!

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Solution:

Find 1/3 of 63.

63 / 3 = 21

21 students gave a speech today.

63 - 21 = 42

Find 2/3 of 42.

42 / 3 = 14

14 x 2 = 28

28 of the remaining students gave their speeches.

42 - 28 = 14

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Answer:

14 students haven't given their speeches!

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Hope This Helped! Good Luck!

7 0

2 years ago