Write standard form twenty-five thousand, four hundred eight

Two mechanics worked on a car. The first mechanic worked for 20 hours, and the second mechanic worked for 15 hours. Together the

posledela

Let's call x1: The rate per hour of the number one mechanic. X2: The rate per hour of mechanic number two. The first thing you should do is identify the system of equations that best describes the problem. In this case it is a system of 2 equations with two unknowns which when solved gives a total of x1 = 85 $ / h and x2 = 50 $ / h. Attached solution.

5 0

3 years ago

What is the value of x??? !!

statuscvo [17]

The data is a little bit complex,but you can use the knowledge of vector in the subject of algebra,or you can ultimate the basic Euclidean knowledge,like cosine theorem.In detail,you can list two equation with two variable,and get the answer.but i don't finish calculating it.

3 0

3 years ago

Giving brainliest to the answer who gives step by step examples clearly!

Anarel [89]

Hi there!

This should be easy,lol!

Answer:

$\sqrt[3]{-128} = \boxed{-128 \sqrt{3} }$ (Decimal: -221.702503)

$\sqrt[3]{162} = \boxed{162 \sqrt{3} }$ (Decimal: 280.592231)

$\sqrt[3]{-1000x^4} = \boxed{-1732.050808x^4}$

Sorry bout the explanation thingy. Their really long -.-!

But the last one is short so i'll put it for you!

Step-by-step explanation:

∴!For the last one!∴

$\sqrt[3]{-1000x^4}$

Simplifies to:

$= - 1732.050808 * x^4$

$= - 1732.050808 * ( x * x * x * x)$

$= - 1732.050808x^4$

Have a great day/night!

7 0

3 years ago

Read 2 more answers

Helppppp please? on a timer so need it ASAP

Irina18 [472]

Answer:

I think its 2!

Step-by-step explanation:

5 0

3 years ago

How many 4 digit numbers are there with the sum of the four digits equal to 34

Masteriza [31]

Answer:

Step-by-step explanation:

THE LARGEST 4 DIGIT NUMBER IS 9999 WHICH HAS SUM OF DIGITS 9+9+9+9 =36 SO TO HAVE A SUM OF DIGITS 34 ,WE HAVE TO TAKE 2 AWAY THERE ARE TWO WAYS TO DO THAT IS

1) TAKE 2 AWAY FROM 1 OF THE 9"S AND THE SET OF THE DIGITS (7,9,9,9)

2)TAKE 1 AWAY FROM 2 OF THE 9"S AND THE SET OF DIGITS (8,8,9,9)

THERE ARE 4 ARRANGEMENTS OF THE DIGITS (7,9,9,9) BECAUSE THERE ARE FOUR POSITIONS FOR THE DIGITS THOUSANDS,HUNDREDES,TENS AND UNITS SO WE CAN PICK A P[OSITION FOR THE 7 IN (4,1) = FOUR WAYS ( THERE ARE 7,9,9,9, 9,7,9,9, 9,9,7,9, 9,9,9,7

THERE ARE SIX ARRANGEMENTS OF THE DIGITS (8,8,9,9, BECAUSE THERE ARE FOUR POSITIONF FOR THE DIGITS THOUSANDS , HUNDRED , TENS AND UNITS SO WE CAN PICK A POSITIONS FOR THE 28"S IN (4,2) = 6 WAYS THEY ARE 8,8,9,9, 8,9,8,9, 8,9,9,8, SO THAT 4+6 OR 10 WAYS

3 0

3 years ago