Answer
school building, so the fourth side does not need Fencing. As shown below, one of the sides has length J.‘ (in meters}. Side along school building E (a) Find a function that gives the area A (I) of the playground {in square meters) in
terms or'x. 2 24(15): 320; - 2.x (b) What side length I gives the maximum area that the playground can have? Side length x : [1] meters (c) What is the maximum area that the playground can have? Maximum area: I: square meters
Step-by-step explanation:
Easy!!!!! its zero!!!!! LOL
Answer:
She uses 243 beads for the 5th string.
Step-by-step explanation:
In this problem, we can see a pattern. If she triples the number of beads in each of the next strings, that means that we just take the last number and multiply by 3. If the first string uses 3, then:
The second uses 9, 3 * 3 = 9
The third uses 27, 9 * 3 = 27
The fourth uses 81, 27 * 3 = 81
And the 5th uses 243, 81 * 3 = 243.
You can find that out by first putting two equations in slope-intercept form y=mx+b by solving for y.
3y - x = 2
3y = x+2
y = (1/3)x + 2/3
9y = 3x + 6
y = (3/9)x + 6/9
y = (1/3)x + 2/3
They are the same line as you can see in the final step.
Since the two lines are the same line, (they "coincide") they are coincident.
Coincident means there are an infinite number of solutions, and since they are the same line, there are an infinite number of solutions.
