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Yakvenalex [24]
3 years ago
6

Triangle TRE has vertices T(3,6), R(-3,10), and E(-9,4). Find the coordinates of point M if line TM is a median of triangle TRE

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
7 0

Answer:

The coordinate of point M = (-6,7)

Explanation:

The Median of a triangle is a line segment from a vertex to the midpoint of the opposite side of a triangle.

Given: \triangle TRE has vertices T(3,6) , R(-3,10) and E(-9,4).

Here, line TM is a median of triangle TRE where M is the midpoint of RE.

The midpoint of  M of the line segment from R(-3,10)  to E(-9,4) is;

M = (\frac{-3+(-9)}{2}, \frac{10+4}{2}) = ( \frac{-12}{2}, \frac{14}{2} )=(-6,7)

Therefore, the coordinate of point M is, (-6,7).

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Answer:

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Step-by-step explanation:

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In triangle abc, ab=90 in, bc=80 in, and angle b measures 50°. what is the approximate perimeter of the triangle?
Arlecino [84]
You need to use the Law of Cosines:
AC² = AB² + BC² - 2·AB·BC·cos(b)
       
Therefore, you get:

AC = √(90² + 80² - 2·90·80·cos(50)
      =√5243.86
      = 72.4 in

Now you can sum up all the sides in order to find the perimeter:

AB + BC + AC = 90 + 80 + 72.4 = 242.4 in

The correct answer is A) 242.4 in

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3 years ago
A survey of 1000 high school students found that 781 students own a cell phone and 133 of those students who own a cell phone al
kirza4 [7]

This question is not complete. Find attached the complete question and the figure showing the two way table.

Answer:

a. P(owns a cellphone) = 781/1000

b. P(does not own a PS4) = 421/500

c. P(owns a PS4 U does not own a cellphone) = 377/1000

d. P(owns a PS4 n does not own a cellphone) = 25/158

e. P(owns a PS4 | own a cell phone) =

158/1000

f. P(owns a cellphone | own a PS4) = 781/1000

Step-by-step explanation:

Total number of students = 1000 students

We have two variables,

1. The students who own cellphones

2. The students who own PS4

a. P(owns a cellphone)

From the question and the table, we are told that 781 people own cellphones.

Hence, P(owns a cellphone) = 781/1000

b. P(does not own a PS4)

From the attached table, we can see that the number of students that does not own a PS4 = 842

Hen P(does not own a PS4) = 842/1000 = 421/500

c. P(owns a PS4 U does not own a cellphone) =

First we find the Probability of student that owns a PS4

Number of students that own a PS4 = 158

P(owns a PS4 ) = 158/1000

Number of students that does not own a cell phone = 219

P(does not own a cell phone) = 219/1000

Therefore, P(owns a PS4 U does not own a cellphone) = P(owns a PS4 ) + P(does not own a cell phone)

= 158/1000 +219/1000

= 377/1000

d. P(owns a PS4 n does not own a cellphone) =

From the table, we obtain that as =

25/158

e. P(owns a PS4 | own a cell phone) =

P(owns a PS4 n own a cell phone) ÷ P(own a cell phone)

= P(owns a PS4)

From the table that would give us = 158/1000

f. P(owns a cellphone | own a PS4) =

P(owns a cellphone n own a PS4) ÷ P(own a PS4)

= P(owns a cellphone

From the table, this is given as :

781/1000

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7 0
3 years ago
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