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Nookie1986 [14]
2 years ago
5

Ldentify the domain and range of each function.

Mathematics
2 answers:
I am Lyosha [343]2 years ago
6 0

the domain is the set of x -values, the range is the set of y-values. I would have to say the domain is : R [ negative intinity, to infinity]. Equally, I would have to say the range is R [ Negative infinity,  to infinity]

Step-by-step explanation:

Why, because no set is defined for either x or y.

sattari [20]2 years ago
4 0

Answer:

The domain of this function is:

C.) Negative infinity to infinity

The range of this function is:

A.) 0 to infinity

Y=4^x-5+3

The domain of this function is:

C.) Negative infinity to infinity

The range of this function is:

B.) 3 to infinity

Answer:

Answer:

Domain : R

Range : R

Step-by-step explanation:

The given function is  or it can be written as y = 15x.

So, the function is valid for all real values of x and we will get the real value of y for each real value od x.

Hence, all the real numbers or R is the domain of the function.

And all the real numbers or R is the range of the given function. (Answer)

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I really need help with this pleaseeee
Sedaia [141]

Answer:

σ = 11.68

Step-by-step explanation:

σ =  \sqrt{ \frac{Σ{(xi -  μ)}^{2} }{N} } \\ where \: σ = population \: standard \: deviation \\ xi = each \: value \: from \: population \\  μ = population  \: mean \\ N = size \: of \: population

σ =  \sqrt{ \frac{Σ{(9 - 26)}^{2} + {(16 - 26)}^{2} +{(30 - 26)}^{2} +{(35 - 26)}^{2} + {(40 - 26)}^{2}}{5} } \\ σ =  \sqrt{ \frac{Σ{((-17)}^{2} + {(- 10) }^{2} +{(4) }^{2} +{(9) }^{2} +{(14) }^{2})}{5}} \\ σ =  \sqrt{ \frac{Σ ({289} + {100} +{16} +{81} + {196})}{5} } \\ σ =  \sqrt{ \frac{682}{5} }  \\ σ  =  \sqrt{136.4} \\  σ = 11.679041056525\\ σ = 11.68

4 0
3 years ago
At the instant the traffic light turns green, an automobile starts with a constant acceleration a of 2.70 m/s2. at the same inst
77julia77 [94]

You know that t=0 and x=0, the car starts moving with a constant acceleration of 2.70m/s²

At the same time, a truck moving speed o 8.50 m/s passes the car

D=v.t (for the truck)

And d= v.t+1/2.a.t²(for the car)

v.t=1/2.a.t²

t=2.v/a

t=2.8.50 m/s/ 2.70 m/s²

17m/2.70=6.29

This mean that the distance is  

D=v.t=8.50m/s.6.29= 53.465 m/s

The speed of the car is  

Vcar=a.t

2.7m/s2×× 53.65

=144.34


4 0
3 years ago
I need help please answer correct please
eduard

Answer:

I believe the answer is 8m.

Step-by-step explanation:

5 0
3 years ago
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REY [17]

Answer:

definition of constant

Step-by-step explanation:

the definition of constant is occurring countinuosly over a period of time

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3 years ago
17+4h+2=1-5h what does the variable equal ?
olga2289 [7]
1. 17+4h+2=1-5h
2. 19+4h=1-5h
3. 18+4h=-5h
4. 18=-9h
5. -2=h
5 0
3 years ago
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