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3 years ago

What is the excluded value of a/b-2

Mathematics

1 answer:

Readme [11.4K]3 years ago

8 0

The correct excluded value is 2.

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Write 0.3 as a fraction in simplest form.

s344n2d4d5 [400]

The question is asking to convert the said decimal value in a simplest fraction form, base on my research and further calculation, I would say that the answer would be 3/10. I hope you are satisfied with my answer and feel free to ask for more

6 0

3 years ago

What is 7a +6c+9a-15c

jeka94

7a + 6c + 9a - 15c

-- Look for all the 'a's 7a, 9a

-- Addum up 16a

-- Look for all the 'c's 6c, -15c

-- Addum up -9c

-- Write the results 16a - 9c

3 0

3 years ago

Read 2 more answers

× + 2y = -4 wite that equation in slope intercept form

Taya2010 [7]

X + 2y = -4
-x -x

2y = -x - 4

Divide all by 2

y = -x/2 - 2

y = (-1/2)x - 2

3 0

3 years ago

Read 2 more answers

adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the

Zigmanuir [339]

Answer:

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$ and $\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

Step-by-step explanation:

The equation of the isotope decay is:

$\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }$

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

$\tau = \frac{5568\,years}{\ln 2}$

$\tau \approx 8032.926\,years$

The decay time is:

$t = 1315\,years + 2007\,years \pm 13\,years$ (There is no a year 0 in chronology).

$t = 3335 \pm 13\,years$

Lastly, the relative amount is estimated by direct substitution:

$\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$

$\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

4 0

3 years ago

after the holiday season, the average number of costumers per day at the game galaxy store decreased from 612 to 450. find the p

andrey2020 [161]

Simple, finding markdown, use these two formulas.

Markdown=Original-New
and
Percent Markdown= Markdown Amount/Original*100

So,

Markdown=612-450
M=162

Markdown%= 162/612*100
M%=0.2647*100
M%=26.5 (rounded)

Thus, there was a 26.5% decrease.

5 0

3 years ago