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Lilit [14]
4 years ago
6

Assume that there are 6 different issues of Time, 7 different issues of Sports Illustrated, and 4 different issues of Popular Sc

ience, including the December 1st issue, on the rack. You choose 4 of them at random.. . What is the probability that you choose the December 1st issue of Popular Science?
Mathematics
1 answer:
rjkz [21]4 years ago
3 0
<span>We have a total amount of outcomes at: 

6+4+7 = 17

</span>Thus, let us compute the chance of NOT picking the Popular Science magazine needed (since each event is independent of one another):<span>
P(E1) P(E2) P(E3) = 16/17 * 15/16 * 14/15 * 13/14 = 16P4/17P4 = 13/17

</span><span>Therefore the probability of picking the December 1st edition is:
</span><span>
1 - P(En) = 1 -13/17 = 4/17

</span><span>The probability of picking the December 1st edition is 4/17.
</span><span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span>
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the answer is 3000 pounds.

Step-by-step explanation:

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2) Describe the transformation that took place on the graph below. Explain how you can be sure.
Slav-nsk [51]

Answer:

The transformation on the graph is a reflection across the x-axis.

Step-by-step explanation:

A reflection is a transformation representing a flip of a figure. Figures may be reflected in a point, a line, or a plane. When reflecting a figure in a line or in a point, the image is congruent to the preimage. A reflection maps every point of a figure to an image across a fixed line.

In this particular figure, you see that each point is the same number of units away from the x-axis. For instance, with A and A' their both 1 unit away from the x-axis. So this is an automatic indicator that this transformation is a reflection.

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Could the equation. For the graph of the function have degree 4?explain
aivan3 [116]

The graphed polynomial seems to have a degree of 2, so the degree can be 4 and not 5.

<h3>Could the graphed function have a degree 4?</h3>

For a polynomial of degree N, we have (N - 1) changes of curvature.

This means that a quadratic function (degree 2) has only one change (like in the graph).

Then for a cubic function (degree 3) there are two, and so on.

So. a polynomial of degree 4 should have 3 changes. Naturally, if the coefficients of the powers 4 and 3 are really small, the function will behave like a quadratic for smaller values of x, but for larger values of x the terms of higher power will affect more, while here we only see that as x grows, the arms of the graph only go upwards (we don't know what happens after).

Then we can write:

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So it is equivalent to a quadratic polynomial.

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3 years ago
What is Xavier’s available lot coverage?
slavikrds [6]

Answer:

<h2> <em><u>720</u></em><em><u>0</u></em></h2>

Step-by-step explanation:

<h3>At first:</h3>

<em><u>G</u></em><em><u>i</u></em><em><u>v</u></em><em><u>e</u></em><em><u>n</u></em><em><u>,</u></em>

Back of lot of the trapezoid = 175

Front of lot of the trapezoid = 185

Length of lot of the trapezoid = 100

<em><u>Therefore</u></em><em><u>,</u></em><em><u> </u></em>

Area of the trapezoid

=  \frac{a + b}{2} c

  • <em>[</em><em>On</em><em> </em><em>putting</em><em> </em><em>the</em><em> </em><em>values</em><em>]</em>

=  \frac{175 + 185}{2}  \times 100

  • <em>[</em><em>On</em><em> </em><em>Simplification</em><em>]</em>

= 360 × 50

  • <em>[</em><em>On multiplying</em><em>]</em>

= 18000

<em><u>Hence</u></em><em><u>,</u></em>

We got the <em>T</em><em>otal Area </em><em>as</em><em> </em><em>180</em><em>0</em><em>0</em><em>.</em>

<h3>Now:</h3>

<em><u>As</u></em><em><u> </u></em><em><u>per</u></em><em><u> </u></em><em><u>given</u></em><em><u> </u></em><em><u>equation</u></em><em><u>,</u></em>

  • \frac{40}{100}  =  \frac{x}{total \: area}
  • To find the value of x

<em><u>Solution</u></em><em><u> </u></em><em><u>,</u></em>

=  > \frac{40}{100}  =  \frac{x}{total \: area}

  • <em>[</em><em>On</em><em> </em><em>putting</em><em> </em><em>Total</em><em> </em><em>Area</em><em> </em><em>=</em><em> </em><em>180</em><em>0</em><em>0</em><em>]</em>

=  > \frac{40}{100}  =  \frac{x}{18000}

  • <em>[</em><em>On</em><em> </em><em>cross</em><em> </em><em>multiplication</em><em>]</em>

=> 40 × 18000 = 100 × x

  • <em>[</em><em>O</em><em>n</em><em> </em><em>Simplification</em><em> </em><em>]</em>

=> 720000 = 100x

  • <em>[</em><em>On</em><em> </em><em>dividing</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>with</em><em> </em><em>100</em><em>]</em>

=  >  \frac{720000}{100}  =  \frac{100x}{100}

  • <em>[</em><em>On</em><em> </em><em>Simplification</em><em> </em><em>]</em>

=> x = 7200

<em><u>Hence</u></em><em><u>,</u></em>

<em><u>Xavier's</u></em><em><u> </u></em><em><u>avaliable</u></em><em><u> </u></em><em><u>lot</u></em><em><u> </u></em><em><u>coverage</u></em><em><u> </u></em><em><u>(</u></em><em><u>x</u></em><em><u>)</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>720</u></em><em><u>0</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

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3 years ago
In the number 12.345, the 3 is in the ________ place.
Kamila [148]

Answer:

The value of 3 is in the tenths place.

Step-by-step explanation:

Given : Number 12.345.

To find : In the number 12.345, the 3 is in the what place ?

Solution :

According to place value system,

Tens   Ones    Tenths     Hundredths     Thousandths

  1           2           3                    4                       5

The value are 12.345=1\times 10+2\times 1+3\times 0.1+4\times 0.01+5\times 0.001

Therefore, The value of 3 is in the tenths place.

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