Answer:
x=9
Step-by-step explanation:
So first subtract 8 on both Sides
3x+8-8=35-8
3x=27
Now divide 3 on both sides to isolate the variable x
x=9
So x=9
Neighborhood A :
first, put the numbers in order...
2,[2,2],4,(4),5,[5,5],5
5 number summary :
minimum = 2
Q1 = 2
Q2 (median) = 4
Q3 = 5
maximum = 5
IQR = Q3 - Q1......5 - 2 = 3...so the IQR = 3
Neighborhood B :
1,[1,2],2,(3),4,[5,5],12
5 number summary :
minimum = 1
Q1 = (1 + 2) / 2 = 3/2 or 1.5
Q2 (median) = 3
Q3 = 5
maximum = 12
IQR = Q3 - Q1....5 - 1.5 = 3.5
are the box plots symmetrical ?
Neighborhood A : the median is 4.....the minimum is 2....so thats 2 spaces from the median...the maximum is 5....so thats 1 space from the median...and being that they are not the same distance from the median, ur box plot is skewed to the left...so this is not symmetrical
Neighborhood B : the median is 3....the minimum is 1....so thats 2 spaces from the median...the maximum is 12....so thats 10 spaces from the median....these are not symmetrical especially since u have an outlier of 12....this is skewed to the right
The answer is 8 because 8 x 8 = 64 If you see these kinds of problem what is the square root of 25, 64, 36... means 5 x 5 = 25, 8 x 8 = 64, 6 x 6 = 36 If you see square root of 48. It would come out to be a decimal number.
Check the picture below.
how do we know? well, notice h(t), starts off at 12, up up up reaches 47.84 then down down down, which is pretty much the trajectory of a flying object, by the time it gets to 44, is still going down.
now, let's look at g(t), starts off at 10, and goes up up up, never down, by the time it gets to 41, is still going up,
so at second 2, h(t) is 44 and going down, g(t) is 41 and going up, at 2.2 h(t) is 40.16, and g(t) is 44.1, between that lapse, h(t) became 44, 43, 42, 41, in the same lapse g(t) became 41, 42, 43, 44, so somewhere in those values h(t) = g(t).
what does the solution mean? It's the seconds or the instant lapse when the first cannon ball was at the same height as the second cannonball.
