Answer:
The graph is sketched by considering the integral. The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.
Step-by-step explanation:
We sketch the integral ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ. We consider the inner integral which ranges from r = 0 to r = 6/cosθ. r = 0 is located at the origin and r = 6/cosθ is located on the line x = 6 (since x = rcosθ here x= 6)extends radially outward from the origin. The outer integral ranges from θ = 0 to θ = π/4. This is a line from the origin that intersects the line x = 6 ( r = 6/cosθ) at y = 1 when θ = π/2 . The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.
Answer:
Of the given geometric sequence, the first term a is 6 and its common ratio r is 2.
Step-by-step explanation:
Recall that the direct formula of a geometric sequence is given by:
Where <em>T</em>ₙ<em> </em>is the <em>n</em>th term, <em>a</em> is the initial term, and <em>r</em> is the common ratio.
We are given that the fifth term <em>T</em>₅ = 96 and the eighth term <em>T</em>₈ = 768. In other words:
Substitute and simplify:
We can rewrite the second equation as:
Substitute:
Hence:
![\displaystyle r = \sqrt[3]{\frac{768}{96}} = \sqrt[3]{8} = 2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20r%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B768%7D%7B96%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B8%7D%20%3D%202)
So, the common ratio <em>r</em> is two.
Using the first equation, we can solve for the initial term:
In conclusion, of the given geometric sequence, the first term <em>a</em> is 6 and its common ratio <em>r</em> is 2.
Answer:
-512
Step-by-step explanation:
11pi/12
Note:
2pi = 360°
(11pi/12)(360°/2pi)
330°
No of solutions: 1
Topic: Graphs
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