Question

Solve this quadratic equation by completing the square x^2-4x-13=0

Answer 1

Answer:

x = 2 ± $\sqrt{17}$

Step-by-step explanation:

Given

x² - 4x - 13 = 0 ( add 13 to both sides )

x² - 4x = 13

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 2)x + 4 = 13 + 4

(x - 2)² = 17 ( take the square root of both sides )

x - 2 = ± $\sqrt{17}$ ( add 2 to both sides )

x = 2 ± $\sqrt{17}$ ← exact solutions