Answer:
c
Step-by-step explanation:
Step 1
Solve 3x-y=-63x−y=−6 for yy.
y=6+3xy=6+3x
Step 2
Substitute 6+3x6+3x for yy in the second and third equation.
2\left(6+3x\right)-5z=-52(6+3x)−5z=−5 x-\left(6+3x\right)-2z=-4x−(6+3x)−2z=−4
Step 3
Solve these equations for xx and zz respectively.
x=-\frac{17}{6}+\frac{5}{6}zx=−
6
17
+
6
5
z z=-1-xz=−1−x
Step 4
Substitute -\frac{17}{6}+\frac{5}{6}z−
6
17
+
6
5
z for xx in the equation z=-1-xz=−1−x.
z=-1-\left(-\frac{17}{6}+\frac{5}{6}z\right)z=−1−(−
6
17
+
6
5
z)
Step 5
Solve z=-1-\left(-\frac{17}{6}+\frac{5}{6}z\right)z=−1−(−
6
17
+
6
5
z) for zz.
z=1z=1
Step 6
Substitute 11 for zz in the equation x=-\frac{17}{6}+\frac{5}{6}zx=−
6
17
+
6
5
z.
x=-\frac{17}{6}+\frac{5}{6}\times 1x=−
6
17
+
6
5
×1
Step 7
Calculate xx from x=-\frac{17}{6}+\frac{5}{6}\times 1x=−
6
17
+
6
5
×1.
x=-2x=−2
Step 8
Substitute -2−2 for xx in the equation y=6+3xy=6+3x.
y=6+3\left(-2\right)y=6+3(−2)
Step 9
Calculate yy from y=6+3\left(-2\right)y=6+3(−2).
y=0y=0
Step 10
The system is now solved.
x=-2x=−2 y=0y=0 z=1z=1
Solution
x=-2x=−2
y=0y=0
z=1z=1
Y=3/2x+0
The y-intercept is 0 as the line intercepts at the origin.
-6/-4= 3/2
Hello,
Answer B
y=-x^4+1
y'=-4x^3
y"=-12x² is always <0 : concavity downside.
Answer:
slope = undefined
y-intercept=0
Step-by-step explanation:
theres no y - intercept and the slope of vertical line is undefined
You need to find the ratio (cream: sugar) in order to know the amount of the sugar.
