What is the circumference of a circle if the area is 7.2

WILL GIVE BRAINLIEST!

MAXImum [283]

Answer:

Texting speed

Step-by-step explanation:

It's the dependent variable

5 0

2 years ago

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under a dilation, the point (2,6) is moved to (6,18) what is the scale factor of the dilation? enter your answer in the box

Anestetic [448]

Step-by-step explanation:

The equation of line passing through the two points is $\frac{y-y_{1} }{x-x_{1} }=\frac{y_{2} -y_{1}}{x_{2} -x_{1}}$

When substituted,the equation becomes $\frac{y-6}{x-2}=\frac{18-6}{6-2}$

which when simplified is $y=3\times x$

The line clearly passes through origin.

The distance between two points is $\sqrt{(y_{1}-y_{2} )^{2}+(x_{1}- x_{2} )^{2}}$

Distance between origin and $(2,6)$ is $\sqrt{40}$ .

Distance between origin and $(6,18)$ is $\sqrt{360}$

Scale factor is $\frac{distance\text{ }of\text{ }p_{2}\text{ from origin}}{distance \text{ } of \text{ } p_{1}\text{ from origin}}$

So,scale factor is $\frac{\sqrt{360} }{\sqrt{40} }$

which when simplified becomes 3.

6 0

2 years ago

A currency exchange will convert 1

Eddi Din [679]

Answer: a) 26297.50 b) 124.992870045

Step-by-step explanation:

a) 105.19*250=26297.50

b) 13148/105.19= 124.992870045

6 0

2 years ago

Assume that the population of human body temperatures has a mean of 98.6 degrees F and a standard deviation of 0.62 degrees F. I

dimulka [17.4K]

Answer:

0% probability of getting a mean temperature of 98.2 degrees F or lower.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 98.6, \sigma = 0.62, n = 106, s = \frac{0.62}{\sqrt{106}} = 0.06$

Find the probability of getting a mean temperature of 98.2 degrees F or lower.

This is the pvalue of Z when X = 98.2. So

$Z = \frac{X - \mu}{s}$

$Z = \frac{98.2 - 98.6}{0.06}$

$Z = -6.67$

$Z = -6.67$ has a pvalue of 0.

So there is a 0% probability of getting a mean temperature of 98.2 degrees F or lower.

8 0

2 years ago

If triangle ABC defined by the coordinates A(1,1), B(9,1), C(1,9) is dilated by a scale factor of 1/2

alukav5142 [94]

Answer:

The transformed points of the triangle ABC are $A' (x,y) = \left( \frac{1}{2}, \frac{1}{2}\right)$ , $B'(x,y) = \left(\frac{9}{2}, \frac{1}{2} \right)$ , $C'(x,y) = \left(\frac{1}{2}, \frac{9}{2}\right)$