How much protons,neutrons and electrons does bromine <br> Have

The gravity of Earth is attracting a person towards the center with 500N of gravitational force. The person is exerting a reacti

Maru [420]

The force is being pulled my the gravity or it could be a third party thing like a black hole you feel me

6 0

3 years ago

Imagine that a relativistic train travels past your lecture room at a speed of 0.894 c. The passengers of the train claim that w

Lady bird [3.3K]

Answer:

The length of the train in the frame of the lecture room is 40.59 m.

Explanation:

Given that,

Speed = 0.894 c

Original length = 90.6 m

We need to calculate the length of the train in the frame of the lecture room

Using formula of length contraction

$L=L_{0}\sqrt{1-(\dfrac{v}{c})^2}$

Where, $L_{0}$ =original length

v = speed of train

Put the value into the formula

$L=90.6\sqrt{1-(\dfrac{0.894c}{c})^2}$

$L=90.6\sqrt{1-0.894^2}$

$L=40.59\ m$

Hence, The length of the train in the frame of the lecture room is 40.59 m.

8 0

4 years ago

Ed invented a device used in gasoline pumps to control gas fumes. which of the following would protect him from others copying h

navik [9.2K]

I believe it is called a patent

7 0

3 years ago

It took 500 N of force to push a car 4 meters. How much work was done?

djverab [1.8K]

Answer:

200 J

Explanation:

W = F S

W= 500 x 4

W = 2000

6 0

3 years ago

A4.0 kg object is moving with speed 2.0 m/s. A 1.0 kg object is moving with speed 4.0 m/s. Both objects encounter the same const

Evgesh-ka [11]

Answer:

Both objects travel the same distance.

(c) is correct option

Explanation:

Given that,

Mass of first object = 4.0 kg

Speed of first object = 2.0 m/s

Mass of second object = 1.0 kg

Speed of second object = 4.0 m/s

We need to calculate the stopping distance

For first particle

Using equation of motion

$v^2=u^2+2as$

Where, v = final velocity

u = initial velocity

s = distance

Put the value in the equation

$0= u^2-2as_{1}$

$s_{1}=\dfrac{u^2}{2a}$ ....(I)

Using newton law

$a=\dfrac{F}{m}$

Now, put the value of a in equation (I)

$s_{1}=\dfrac{8}{F}$

Now, For second object

Using equation of motion

$v^2=u^2+2as$

Put the value in the equation

$0= u^2-2as_{2}$

$s_{2}=\dfrac{u^2}{2a}$ ....(I)

Using newton law

$F = ma$

$a=\dfrac{F}{m}$

Now, put the value of a in equation (I)

$s_{2}=\dfrac{8}{F}$

Hence, Both objects travel the same distance.

6 0

3 years ago

How much protons,neutrons and electrons does bromine Have