Question

the angle of elevation of the top of a tree from a distance of 1000 ft is 25 degrees. how tall is the tree?

Answer 1

Answer:

466.30 ft

Step-by-step explanation:

Given in the question,

the angle of elevation of the top of a tree from ground = 25°

horizontal distance between angle of elevation and tree = 1000ft

To find,

height of tree( vertical distance from ground to top of tree)

As we can presume for the question that the whole scenario makes a right angle triangle. So, we will use trigonometry functions

Tan Δ = opposite / adjacent

Tan25°= height / 1000

height = 1000 * Tan25°

height = 1000 * 0.466

height = 466.30 ft

So, the height of tree = 466.30 ft