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3 years ago

5t=24.5 what does t represent

Mathematics

2 answers:

Burka [1]3 years ago

6 0

T represents 4.9 in the problem

T = 4.9

Inessa [10]3 years ago

4 0

Divide both sides by 5 to get t by itself, then you have your answer

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VMariaS [17]

Answer:

Option 2

Step-by-step explanation:

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2 years ago

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3 years ago

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Step-by-step explanation:

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3 years ago

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Use a graphing utility to graph the function and the damping factor of the function in the same viewing window.

Bas_tet [7]

Answer:

The function touches the damping factor

at x= $\frac{(4n-3)\pi}{2}$ and x= $\frac{(4n-1)\pi}{2}$

The x-intercept of f(x) is

at x= $n\pi$

Step-by-step explanation:

Given function is f(x)= $e^{-3x} sin(x)$ and damping factor as y= $e^{-3x}$ and y= $(-1)e^{-3x}$

To find when function touches the damping factor:

For f(x)= $e^{-3x} sin(x)$ and y= $e^{-3x}$

Equating the both the equation,

$e^{-3x} sin(x)=e^{-3x}$

$sin(x)=1$

x= $\frac{(4n-3)\pi}{2}$

For f(x)= $e^{-3x} sin(x)$ and y= $(-1)e^{-3x}$

Equating the both the equation,

$e^{-3x} sin(x)=(-1)e^{-3x}$

$sin(x)=(-1)$

x= $\frac{(4n-1)\pi}{2}$

Therefore, The function touches the damping factor x= $\frac{(4n-3)\pi}{2}$ and x= $\frac{(4n-1)\pi}{2}$

To find x-intercept of f(x):

For x-intercept, y=0

f(x)= $e^{-3x} sin(x)$

y= $e^{-3x} sin(x)$

$e^{-3x} sin(x)=0$

Hence, $e^{-3x}$ is always greater than zero.

Therefore, $sin(x)=0$

x= $n\pi$

Thus,

The x-intercept of f(x) is at x= $n\pi$

7 0

3 years ago