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Lemur [1.5K]
3 years ago
8

How can graphing help solve a problem involving ratios

Mathematics
1 answer:
maria [59]3 years ago
4 0
Graphing can help solve a problem involving ratios by showing you the rate of 2 different ratios. You can then see the difference of each ratio based on the unit rate.
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VX
zhenek [66]

Answer:

The vertical line test can be used to determine whether a graph represents a function. If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because a function has only one output value for each input value.

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Hope it help you

6 0
3 years ago
GET BRAINLIEST FOR THE CORRECT ANSWER AND EXPLANATION!
Tresset [83]

Interpreting the inequality, it is found that the correct option is given by F.

------------------

  • The first equation is of the line.
  • The equal sign is present in the inequality, which means that the line is not dashed, which removes option G.

In standard form, the equation of the line is:

x + 2y = 6

2y = 6 - x

y = -0.5x + 2

Thus it is a decreasing line, which removes options J.

  • We are interested in the region on the plane below the line, that is, less than the line, which removes option H.

------------------

  • As for the second equation, the normalized equation is:

3x^2 + 3y^2 = 12

3(x^2 + y^2) = 12

x^2 + y^2 = 4

  • Thus, a circle centered at the origin and with radius 2.
  • Now, we have to check if the line x + 2y - 6 = 0, with coefficients a = 1, b = 2, c = -6, intersects the circle, of centre x = 0, y = 0
  • First, we find the following distance:

d = \sqrt{\frac{|ax + by + c|}{a^2 + b^2}}

  • Considering the coefficients of the line and the center of the circle.

d = \sqrt{\frac{|1(0) + 2(0) - 6|}{1^2 + 2^2}} = \sqrt{\frac{6}{5}} = 1.1

  • This distance is less than the radius, thus, the line intersects the circle, which removes option K, and states that the correct option is given by F.

A similar problem is given at brainly.com/question/16505684

3 0
3 years ago
144 in the ratio 3:4​
Nataly_w [17]

Answer: 132

Step-by-step explanation:

5 0
3 years ago
Is an angle that is greater than 90 degrees is acute True or False
Brilliant_brown [7]
Hey there!

The answer is false. A 90 degree angle is called a right triangle. Any angle less than 90 degree is called an acute angle. Any angle more than 90 degree is called an obtuse angle
7 0
3 years ago
Read 2 more answers
Choose all that correctly solve for the variable x
Ratling [72]
<h2>✔Answer</h2><h2>1. X = 3</h2><h2 /><h2>2. </h2><h2>\frac{7}{2}</h2><h2>3.</h2>

<h2>\frac{5}{6}</h2>

<h2>Hope it Helps❤</h2>
6 0
2 years ago
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