Answer:
(x+5/2)^2 = 0
Step-by-step explanation:
4 x^{2} +20x +25 =0
Divide by 4
4/4 x^{2} +20/4x +25/4 =0
x^2 +5x +25/4 =0
Subtract 25/4 from each side
x^2 +5x +25/4 -25/4 =-25/4
x^2 +5x =-25/4
Take the coefficent of x
5
Divide by 2
5/2
Square it
25/4
Add it to each side
x^2 +5x +25/4 =-25/4+25/4
(x+5/2)^2 = 0
Take the square root of each side
x+5/2 = 0
x = -5/2
Answer:
(28 + h + p)/4 = k
Step-by-step explanation:
Step 1: Write equation
h + p = 4(k - 7)
Step 2: Solve for <em>k</em>
<u>Distribute 4:</u> h + p = 4k - 28
<u>Add 28 to both sides:</u> 28 + h + p = 4k
<u>Divide both sides by 4:</u> (28 + h + p)/4 = k
Explanation:
A sequence is a list of numbers.
A <em>geometric</em> sequence is a list of numbers such that the ratio of each number to the one before it is the same. The common ratio can be any non-zero value.
<u>Examples</u>
- 1, 2, 4, 8, ... common ratio is 2
- 27, 9, 3, 1, ... common ratio is 1/3
- 6, -24, 96, -384, ... common ratio is -4
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<u>General Term</u>
Terms of a sequence are numbered starting with 1. We sometimes use the symbol a(n) or an to refer to the n-th term. The general term of a geometric sequence, a(n), can be described by the formula ...
a(n) = a(1)×r^(n-1) . . . . . n-th term of a geometric sequence
where a(1) is the first term, and r is the common ratio. The above example sequences have the formulas ...
- a(n) = 2^(n -1)
- a(n) = 27×(1/3)^(n -1)
- a(n) = 6×(-4)^(n -1)
You can see that these formulas are exponential in nature.
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<u>Sum of Terms</u>
Another useful formula for geometric sequences is the formula for the sum of n terms.
S(n) = a(1)×(r^n -1)/(r -1) . . . . . sum of n terms of a geometric sequence
When |r| < 1, the sum converges as n approaches infinity. The infinite sum is ...
S = a(1)/(1-r)
There's no diagram here so I can't be specific, but I've attached an image.
Answer:
$4
Step-by-step explanation:
