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OLEGan [10]
3 years ago
5

Systems w/ substitution y=4x+6 & y=-5+21

Mathematics
1 answer:
Law Incorporation [45]3 years ago
7 0
So basically what you would is u would plug the first equation into the second equation. -5x+21=4x+6
                      -21      -21
-5x=4x-15
-4x   -4x
-9x=-15
-9x/-9=15/-9
x=-1.66
then you would plug x back into the equation to get your y value
y=4(-1.66)+6
y=6.64+6
y=12.64



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Answer:

A = B + 52

Step-by-step explanation:

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Solve the following quadratic by<br> completing the square.<br> y = x2 - 6x +2
eduard

Answer:

Roots of the equation are  (−3−√7) , (−3+√7)

Step-by-step explanation:

For solving a quadratic equation using completing the square method:

  • set the value of 'y' = 0
  • add and subtract the square of half of the coefficient of x.
  • solve the obtained equation for 'x'

given equation:

y = x^2 - 6x +2

0 = x^2 - 6x + 2

0 = x^2 - 3^2 + 3^2 -6x +2

0 = (x-3)^2 -7

7 =  (x-3)^2

±\sqrt{7} = x-3

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learn more about quadratic equations at

brainly.com/question/17177510

#SPJ10

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