Answer:
the green box is 0
Step-by-step explanation:
we are asked to find the <u>x-intercept</u>, which means y = 0
(x, y)
Another way to test this is plug it in 1 for x! (1, y) where x = 1






y = 0
Answer:
The first derivative of
(r(t)=5*t^{-2}) with respect to t is
(r'(t) = -10*t^{-3}).
Step-by-step explanation:
Let be
, which can be rewritten as
. The rule of differentiation for a potential function multiplied by a constant is:
, 
Then,

(r'(t) = -10*t^{-3})
The first derivative of
(r(t)=5*t^{-2}) with respect to t is
(r'(t) = -10*t^{-3}).
Take

so that you have

which gives a Jacobian determinant of

So upon transforming the coordinates to the u-v plane, you have (and I'm guessing on what the integrand actually is)
