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notka56 [123]
2 years ago
8

Solve the following quadratic by completing the square. y = x2 - 6x +2

Mathematics
1 answer:
eduard2 years ago
4 0

Answer:

Roots of the equation are  (−3−√7) , (−3+√7)

Step-by-step explanation:

For solving a quadratic equation using completing the square method:

  • set the value of 'y' = 0
  • add and subtract the square of half of the coefficient of x.
  • solve the obtained equation for 'x'

given equation:

y = x^2 - 6x +2

0 = x^2 - 6x + 2

0 = x^2 - 3^2 + 3^2 -6x +2

0 = (x-3)^2 -7

7 =  (x-3)^2

±\sqrt{7} = x-3

±\sqrt{7} + 3 = x

learn more about quadratic equations at

brainly.com/question/17177510

#SPJ10

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a) 5  b) 1  c) 0  d) -4

Explanation:

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Ok, there's a lot going on. You will want to follow PEMDAS, the acronym of the Order of Operations. It stands for Parentheses, Exponents, Multiplication/Division, and Addition/Subtraction. The M/D can be switched depending on what comes first from left to right, and same goes for A/S.

First, start off by doing everything in the brackets.

Let's add 1/2 and 1/4. To add fractions, they have to have a common denominator. I'm making 1/2 into 2/4 but multiplying the top and bottom by 2. Now it is 2/4 + 1/4 so we can add to get <u>3/4</u>.

The other thing inside the brackets is 2(1/8). We can just multiply straight across and get 2/8. This can be simplified to <u>1/4</u>.

Now, we add 3/4 and 1/4. The denominators are already the same, so we can just add them together to get 4/4 or 1.

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The answer to question a is <u><em>5</em></u>.

b) √(0.6)² + (0.8)²

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0.8 • 0.8 = 0.64

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The answer to question b is <u><em>1</em></u>.

c) (1/5 - 3/5) • √6•3/2 + (√36 ÷ √5²)

Let's start with the first bit: (1/5 - 3/5)

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The third section: (\sqrt{36}÷ \sqrt{5^{2} })

The square root of 36 = 6 (because 6•6=36, so it's right)

The square root and the square cancel each other out, so the second part is 5.

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