Answer:
![x = 49.8^\circ\\y = 54.6^\circ](https://tex.z-dn.net/?f=x%20%3D%2049.8%5E%5Ccirc%5C%5Cy%20%3D%2054.6%5E%5Ccirc)
Step-by-step explanation:
Kindly refer to the image attached in the answer region for labeling of triangle.
<em>AB </em><em>= 16
</em>
<em>BC </em><em>= 19</em>
<em>AC </em><em>= 15
</em>
![\angle ABC = x^\circ\\\angle ACB = y^\circ](https://tex.z-dn.net/?f=%5Cangle%20ABC%20%3D%20x%5E%5Ccirc%5C%5C%5Cangle%20ACB%20%3D%20y%5E%5Ccirc)
We have to find the <em>angles </em><em>x</em> and <em>y</em> i.e.
.
Formula for <em>cosine rule</em>:
![cos B = \dfrac{a^{2}+c^{2}-b^{2}}{2ac}](https://tex.z-dn.net/?f=cos%20B%20%3D%20%5Cdfrac%7Ba%5E%7B2%7D%2Bc%5E%7B2%7D-b%5E%7B2%7D%7D%7B2ac%7D)
Where
<em>a</em> is the side opposite to
,
<em>b</em> is the side opposite to
and
<em>c</em> is the side opposite to
.
![\Rightarrow cos x = \dfrac{19^{2}+16^{2}-15^{2}}{2 \times 19 \times 16}\\\Rightarrow cos x = \dfrac{392}{608} \\\Rightarrow x = 49.8^\circ](https://tex.z-dn.net/?f=%5CRightarrow%20cos%20x%20%3D%20%5Cdfrac%7B19%5E%7B2%7D%2B16%5E%7B2%7D-15%5E%7B2%7D%7D%7B2%20%5Ctimes%2019%20%5Ctimes%2016%7D%5C%5C%5CRightarrow%20cos%20x%20%3D%20%5Cdfrac%7B392%7D%7B608%7D%20%5C%5C%5CRightarrow%20x%20%3D%2049.8%5E%5Ccirc)
Similarly, for finding the value of <em>y:</em>
![cos C = \dfrac{a^{2}+b^{2}-c^{2}}{2ab}\\\Rightarrow cos y = \dfrac{19^{2}+15^{2}-16^{2}}{2 \times 19 \times 15}\\\Rightarrow cos y = \dfrac{330}{570}\\\Rightarrow y = 54.6^\circ](https://tex.z-dn.net/?f=cos%20C%20%3D%20%5Cdfrac%7Ba%5E%7B2%7D%2Bb%5E%7B2%7D-c%5E%7B2%7D%7D%7B2ab%7D%5C%5C%5CRightarrow%20cos%20y%20%3D%20%5Cdfrac%7B19%5E%7B2%7D%2B15%5E%7B2%7D-16%5E%7B2%7D%7D%7B2%20%20%5Ctimes%2019%20%5Ctimes%2015%7D%5C%5C%5CRightarrow%20cos%20y%20%3D%20%5Cdfrac%7B330%7D%7B570%7D%5C%5C%5CRightarrow%20y%20%3D%2054.6%5E%5Ccirc)
Hence, the values are:
![x = 49.8^\circ\\y = 54.6^\circ](https://tex.z-dn.net/?f=x%20%3D%2049.8%5E%5Ccirc%5C%5Cy%20%3D%2054.6%5E%5Ccirc)
Answer:
(y^2)/4 square meters
Step-by-step explanation:
For a perimeter length of x, the side of a square will be x/4 and its area will be (x/4)^2.
If one side of the square is shortened by y/2 and the adjacent side is lengthened by y/2, then the difference in side lengths will be y. The area of the resulting rectangle will be ...
(x/4 -y/2)(x/4 +y/2) = (x/4)^2 -(y/2)^2
That is, the difference in area between the square and the rectangle is ...
(x/4)^2 - ((x/4)^2 -(y/2)^2) = (y/2)^2 = y^2/4
The positive difference between the area of the square region and the area of the rectangular region is y^2/4 square meters.
Answer:
you would need to first do
(p times 1.25)
+
(j times 1.85)
and then
22 divided by 33.50
Step-by-step explanation:
18 . it's increasing by 5 every time so the next one after 23 is 28
Answer:
D
Step-by-step explanation:
hope it helps :)
have a nice day or night