Hello,
The median of the temperatures at Springwood is 86. (median is at the middle).
the median of the temperatures at Meadows is 73. (median is at the middle).
The (IQR) interquartile range of the temperatures at Meadows is 12. (You have to subtract both of the IQR left and right 80 - 68 = 12).
The (IQR) interquartile range of the temperatures at Springwood is 14. (You have to subtract both of the IQR left and right 91 - 77 = 14).
the difference of the medians as a multiple of their average interquartile range is 79.5 is average median and 13 average IQR.
Im not 100% sure, but I think the answer is A! Sorry, this probably wasn’t that helpful lol, have a nice day.
The radius r used in below equations would equal 2in because it is half the given diameter of 4in.
The volume of the cone would be
The volume of a cylinder with the same dimensions would be
The cylinder is 24 - 8 = 16 cubic inches greater.
If b equals three
3 subtract 2
Equals one
