Answer: The median of the temperatures at Springwood is <u>86.</u>
The median of the temperatures at Meadows is<u> 73</u>.
The interquartile range of the temperatures at Meadows is <u>12</u>.
The interquartile range of the temperatures at Springwood is <u>14.</u>
The difference of the medians as a multiple of their average interquartile range as : Difference in medians = 13= 1 x 13
i.e. Difference in medians = 1 x (Average interquartile range)
Step-by-step explanation:
In a box - whisker plot , the vertical line in box represents the median value.
The left end of box denotes Lower quartile and the right end of the box Upper quartile.
By considering the given picture,
For Meadows ,
Median = 73
The median of the temperatures at Meadows is<u> 73</u>. (1)
Lower quartile = 68
Upper quartile = 80
Interquartile range = Upper quartile- Lower quartile
Interquartile range=80-68 = 12
The interquartile range of the temperatures at Meadows is <u>12</u>. (2)
For Springwood,
Median = 86
The median of the temperatures at Springwood is <u>86.</u> (3)
Lower quartile = 77
Upper quartile = 91
Interquartile range = Upper quartile- Lower quartile
= 91-77 = 14
The interquartile range of the temperatures at Springwood is <u>14.</u> (4)
Difference in medians = 86-73 = 13 [From (1) and (3)]
Average interquartile range = [From (2) and (4)]
The difference of the medians as a multiple of their average interquartile range as : Difference in medians = 13= 1 x 13
i.e. Difference in medians = 1 x (Average interquartile range)