Answer:
I dont have too much info but its 12.50m
Step-by-step explanation:
12.50(1) is 12.50 12.50(2) is 25 buck and so on and so on
Answer:
24.6 % decrease
Step-by-step explanation:
Let x be the original temperature
Increase by 25%
x + .25x
1.25x
Decrease by 40%
The amount decreased is
(1.25x) *.40
.496x
Subtract that from 1.25x
1.25x - .496x
.754x
We need to find the percent decrease
1 - .754 = .246
24.6 % decrease
Let, the first (smaller) number = x
Larger number = 8x
Then, 8x - x = 70
7x = 70
x = 70/7
x = 10
& 8(10) = 80
In short, Your Numbers would be, 10 & 80
Hope this helps!
Answer:
(a) E(X) = -2p² + 2p + 2; d²/dp² E(X) at p = 1/2 is less than 0
(b) 6p⁴ - 12p³ + 3p² + 3p + 3; d²/dp² E(X) at p = 1/2 is less than 0
Step-by-step explanation:
(a) when i = 2, the expected number of played games will be:
E(X) = 2[p² + (1-p)²] + 3[2p² (1-p) + 2p(1-p)²] = 2[p²+1-2p+p²] + 3[2p²-2p³+2p(1-2p+p²)] = 2[2p²-2p+1] + 3[2p² - 2p³+2p-4p²+2p³] = 4p²-4p+2-6p²+6p = -2p²+2p+2.
If p = 1/2, then:
d²/dp² E(X) = d/dp (-4p + 2) = -4 which is less than 0. Therefore, the E(X) is maximized.
(b) when i = 3;
E(X) = 3[p³ + (1-p)³] + 4[3p³(1-p) + 3p(1-p)³] + 5[6p³(1-p)² + 6p²(1-p)³]
Simplification and rearrangement lead to:
E(X) = 6p⁴-12p³+3p²+3p+3
if p = 1/2, then:
d²/dp² E(X) at p = 1/2 = d/dp (24p³-36p²+6p+3) = 72p²-72p+6 = 72(1/2)² - 72(1/2) +6 = 18 - 36 +8 = -10
Therefore, E(X) is maximized.
Answer:
One solution
Step-by-step explanation:
0.75 (x + 40) = 0.35 (x + 20) + 0.35 (x + 20)
0.75x + 30 = 0.35x + 7 + 0.35x + 7
0.75x + 30 = 0.7x + 14
0.05x + 30 = 14
0.05x = -16
x = -320
Hope this helps!
