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Aleonysh [2.5K]
3 years ago
5

How can you write a fraction equivalent to 60/80 and with a denominator that is less than 80?

Mathematics
1 answer:
storchak [24]3 years ago
4 0

Step-by-step explanation: To write 60/80 that has a denominator less than 80, we can write reduce this fraction.

Notice that 60/80 can be reduced because 60 and 80 have a greatest common factor of 20. So we divide both 60 and 80 by 20 to get 3/4. Now, this is an equivalent fraction that has a denominator that's less than 80. Image is provided below.

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19. 4x-y+2z =<br> 8x+y-4<br> Find x
Varvara68 [4.7K]

Answer:

x = \frac{4-2y+2z}{4}

Step-by-step explanation:

4x-y+2z = 8x+y-4

4x-8x-y+2z = 8x - 8x +y-4

-4x -y +2z= y-4

-4x -y+y +2z = y+y-4

-4x +2z = 2y-4

-4x+2z-2z = 2y-2z-4

-4x = 2y-2z-4

x= \frac{2y-2z-4}{-4} = \frac{4-2y+2z}{4}

4 0
2 years ago
If 14x = ^13√14, what value of x makes this equation true?
Andrews [41]

The value of x is 1/13 (4th choice)

Step-by-step explanation:

{a}^{ \frac{m}{n} }  =  \sqrt[n]{ {a}^{m} }

If 14^x = ¹³√14, what value of <em>x </em>makes this equation true?

\sqrt[13]{14}  =  {14}^{x}  \\  \sqrt[13]{14}  =  {14}^{ \frac{1}{13} }

So, the value of <em>x</em> is 1/13 (4th choice)

<em>Hope</em><em> </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>

6 0
3 years ago
16. Write the inequality that is shown on the graph.
TiliK225 [7]

Answer: 5<x<9

Step-by-step explanation:

Graph is from 5 to 9, not including 5 and 9. Let's say x is all the values from 5 to 9, not including 5 and 9.

So, answer is 5<x<9

3 0
1 year ago
Please explain how u get the answer thanks! <br> (Last question)
love history [14]

Answer:

money made by michael = 15*3 +6*5 = 45+30= $75

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Simplify: 18q2−45q+25/9q2−25.
Svet_ta [14]

Answer:

\frac{(6q-5)}{(3q+5)}

Step-by-step explanation:

Given: \frac{18q^{2}-45q+25 }{9q^{2}-25 }

Factorizing the numerator and the denominator, we have:

18q^{2} - 45q + 25 = 18q^{2} - 30q - 15q + 25

                         = (3q - 5)(6q - 5)

and

9q^{2} - 25 = (3q - 5)(3q + 5)

So that,

\frac{18q^{2}-45q+25 }{9q^{2}-25 } = \frac{(3q-5)(6q-5)}{(3q-5)(3q+5)}

                 = \frac{(6q-5)}{(3q+5)}

Therefore,

\frac{18q^{2}-45q+25 }{9q^{2}-25 } = \frac{(6q-5)}{(3q+5)}

5 0
3 years ago
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