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Lana71 [14]
3 years ago
8

Is this correct or is my math total garbage?​

Mathematics
1 answer:
Dmitrij [34]3 years ago
5 0

Step-by-step explanation:

I think your answer is right

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Well,properties can help you because you can shorten or make an equation more understandable, like using distributive property in the example 2(5x-3), you can rewrite it as 10x-6. See?
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44a - 1

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7 0
2 years ago
Triphasil-28 birth control tablets are taken sequentially, 1 tablet per day for 28 days, with the tablets containing the followi
bazaltina [42]

Answer:

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

Step-by-step explanation:

The total milligrams of levonorgestrel is:

L = L_{1} + L_{2} + L_{3}

In which L_{1}, L_{2} and L_{3} are the number of miligrams of levonorgestrel taken in each phase.

The total milligrams of ethinyl estradiol is:

E = E_{1} + E_{2} + E_{3}

In which E_{1},E_{2} and E_{3} are the number of miligrams of ethinyl estradiol taken in each phase.

We can solve this by phase.

Phase 1: 6 tablets, each containing 0.050 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

6*0.050mg = 0.30mg of levonorgestrel and 6*0.030mg = 0.18mg of ethinyl estradiol are taken.

So L_{1} = 0.30 and E_{1} = 0.18

Phase 2: 5 tablets, each containing 0.075 mg of levonorgestrel and 0.040 mg ethinyl estradiol

In this phase,

5*0.075mg = 0.375mg of levonorgestrel and 5*0.040mg = 0.20mg of ethinyl estradiol are taken.

So L_{2} = 0.375 and E_{2} = 0.20

Phase 3: 10 tablets, each containing 0.125 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

10*0.125mg = 1.25mg of levonorgestrel and 10*0.030mg = 0.30mg of ethinyl estradiol are taken.

So L_{3} = 1.25 and E_{3} = 0.30

The total milligrams of levonorgestrel is:

L = L_{1} + L_{2} + L_{3} = 0.30 + 0.375 + 1.25 = 1.925

The total milligrams of ethinyl estradiol is:

E = E_{1} + E_{2} + E_{3} = 0.18 + 0.20 + 0.30 = 0.68

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

6 0
2 years ago
What is the exact circumference of the circle?
fredd [130]
Data:

Formula: diameter = 2*radius

Formula: (<span>Circle length)
</span>C = 2* \pi *r
<span>
Solving: </span><span>Using the data
</span>diameter = 2*radius
20 = 2*r
2r = 20
r =  \frac{20}{2}
\boxed{r = 10\:ft}

<span>Now, replace in the circumference length formula
</span>C = 2 \pi *r
C = 2 \pi *10
\boxed{\boxed{C = 20 \pi \:ft}}\end{array}}\qquad\quad\checkmark

Answer:
<span>The exact circumference of the circle is </span>20 \pi \:ft
7 0
3 years ago
How is 0.009 and 0.9 related
Marysya12 [62]
They are related as they are both decimals, and carry a 9. They are therefore 90th of some strange
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2 years ago
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