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Bas_tet [7]
3 years ago
15

Logarithms are studied for which of the following​ reasons? A. To help in solving exponential equations when relating the bases

cannot be used. B. To make​ student's lives miserable. C. To be able to solve complex logarithmic equations. D. To validate the logarithmic properties.
Mathematics
1 answer:
skad [1K]3 years ago
7 0

Answer:

To help in solving exponential equations when relating the bases cannot be used

Step-by-step explanation:

Recall an equation of the form

a^{x}=b\\ from the expression a^{x}\\, a\\ is the base and the power is {x}\\.

a\neq b\\ it is impossible to carryout the operation since the bases are not equal.

This is where we implore the help of logarithm which help us to bring the base to a come base i.e using the property below

loga^{x}=logb\\x=\frac{logb}{loga} \\.

Hence we can conclude that logarithm helps in solving equations when bases cannot easily be related.

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the question is not so clear

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3 years ago
The school auditorium can hold at most 480 people. There were 185 advance tickets sold for the school play. Write and solve an i
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Answer:

p + 185 ≤ 480

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If a student (represented by initials) was chosen at random, find P(HH|C').
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3/5

Step-by-step explanation:

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2 years ago
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The graph below describes the journey of a train between two cities.
Veseljchak [2.6K]

Answer:

[A] Acceleration in first 15 min = 200  km/h²

[B] Distance between two cities = 125 km

[C] Average Speed of journey =  62.5  km/hr

Step-by-step explanation:

To Solve:

Acceleration in first 15 min

Distance between two cities  

Average speed of journey

Solve:

[A] Work out the acceleration, in km/h?, in the first 15 mins.

Each horizontal block is 1/8 hr = 7.5 min

Each vertical block is 10 km/hr

Time                     Velocity  km/hr

0 Min  ( 0 hr)            0

15 Min (1/4 hr)           50

45 Min (3/4 hr)         50

60 MIn  ( 1 hr)            100

90 Min  ( 3/2 hr)        100

120 Min ( 2hr)            0

Acceleration in first 15 min  (1/4 hr)  =  (50 - 0)/(1/4 - 0)  = 50/(1/4)

= 200  km/h²

Hence, Answer for [A] = 200  km/h²

[B] Work out the distance between the two cities. $60 Velocity (in km/h)

= (1/2)(0 + 50)(1/4 - 0)  + 50 * (3/4 - 1/4)  + (1/2)(50 + 100)(1 - 3/4)  + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)

=  25/4  + 25 + 75/4   + 50 + 25

= 125

Distance between two cities = 125 km

[C] Work out the average speed of the train during 20 the journey.

Average Speed of journey = 125/2  = 62.5  km/hr

[RevyBreeze]

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