Perpendicular lines have slopes that are negative reciprocals to each other, that is, if one slope is a/b, the other is -b/a
in this case, the given slope is 1/3, so the other line's slope is -3/1, which is -3
from the graph we see that the y intercept of line b is -4, so the equation of line b is: y=-3x-4
If you meant 2x + 2x + 1 = 17: x = 4
Solve for x by simplifying both sides of the equation, then isolating the variable.<span>
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If you meant <span>x2 + 2x + 1 = 17:</span> <span>x ≈ 3.1231056,−5.1231056x</span>
Solve the equation for x by finding a, b, and c of the quadratic then applying the quadratic formula. <span><span>x = −1 ± <span>√17</span></span>x</span>
Answer:
¾ = x
Step-by-step explanation:
Since 3 - 0 gives us the 3, we do this:
![0 = -|8x - 6|](https://tex.z-dn.net/?f=0%20%3D%20-%7C8x%20-%206%7C)
0 = -8x + 6 >> Distributive Property
-6 - 6
___________
-6 = -8x
__ ___
-8 -8
¾ = x
I am joyous to assist you anytime.
Answer:
![x=-7](https://tex.z-dn.net/?f=x%3D-7)
Step-by-step explanation:
We have been given an equation
. We are asked to find the zeros of equation by factoring and then find the line of symmetry of the parabola.
Let us factor our given equation as:
![2x^2+28x+96=0](https://tex.z-dn.net/?f=2x%5E2%2B28x%2B96%3D0)
Dividing both sides by 2:
![x^2+14x+48=0](https://tex.z-dn.net/?f=x%5E2%2B14x%2B48%3D0)
Splitting the middle term:
![x^2+6x+8x+48=0](https://tex.z-dn.net/?f=x%5E2%2B6x%2B8x%2B48%3D0)
![(x^2+6x)+(8x+48)=0](https://tex.z-dn.net/?f=%28x%5E2%2B6x%29%2B%288x%2B48%29%3D0)
![x(x+6)+8(x+6)=0](https://tex.z-dn.net/?f=x%28x%2B6%29%2B8%28x%2B6%29%3D0)
![(x+8)(x+6)=0](https://tex.z-dn.net/?f=%28x%2B8%29%28x%2B6%29%3D0)
Using zero product property:
![(x+8)=0\text{ (or) }(x+6)=0](https://tex.z-dn.net/?f=%28x%2B8%29%3D0%5Ctext%7B%20%28or%29%20%7D%28x%2B6%29%3D0)
![x+8=0\text{ (or) }x+6=0](https://tex.z-dn.net/?f=x%2B8%3D0%5Ctext%7B%20%28or%29%20%7Dx%2B6%3D0)
![x=-8\text{ (or) }x=-6](https://tex.z-dn.net/?f=x%3D-8%5Ctext%7B%20%28or%29%20%7Dx%3D-6)
Therefore, the zeros of the given equation are
.
We know that the line of symmetry of a parabola is equal to the x-coordinate of vertex of parabola.
We also know that x-coordinate of vertex of parabola is equal to the average of zeros. So x-coordinate of vertex of parabola would be:
![\frac{-8+(-6)}{2}=\frac{-14}{2}=-7](https://tex.z-dn.net/?f=%5Cfrac%7B-8%2B%28-6%29%7D%7B2%7D%3D%5Cfrac%7B-14%7D%7B2%7D%3D-7)
Therefore, the equation
represents the line of symmetry of the given parabola.