x=3 1/4 is not a solution to the equation.
12 5/8=x+9 1/4 Subtract 9 1/4 from each side 3 3/8=x, but 3 1/4=3 2/8
The local minimum of function is an argument x for which the first derivative of function g(x) is equal to zero, so:
g'(x)=0
g'(x)=(x^4-5x^2+4)'=4x^3-10x=0
x(4x^2-10)=0
x=0 or 4x^2-10=0
4x^2-10=0 /4
x^2-10/4=0
x^2-5/2=0
[x-sqrt(5/2)][x+sqrt(5/2)]=0
Now we have to check wchich argument gives the minimum value from x=0, x=sqrt(5/2) and x=-sqrt(5/2).
g(0)=4
g(sqrt(5/2))=25/4-5*5/2+4=4-25/4=-9/4
g(-sqrt(5/2))=-9/4
The answer is sqrt(5/2) and -sqrt(5/2).
Answer:
1 - 3 (1 quarter is 25 and a dime is 10, so, 3.)
4 - 10
6 - 15
14 - 33
Step-by-step explanation:
Answer:
?
Step-by-step explanation:
Answer:
The coefficient is 7
Step-by-step explanation:
The coefficient of an algebraic expression is the number that is being multiplied by a variable or multiple variables. In this case, 7 is being multiplied by x and y, so 7 is the coefficient.