Answer:
15 ounces per box
Step-by-step explanation:
The rate StartFraction 165 ounces Over 11 boxes EndFraction describes the relationship between the number of boxes and the weight of the crackers in the boxes. What is the weight, in ounces, of one box?
Total weight of crackers in the boxes = 165 ounces
Total number of boxes = 11 boxes
What is the weight, in ounces, of one box?
Weight per box of crackers =
Total weight of crackers in the boxes / Total number of boxes
= 165 ounces / 11 boxes
= 15 ounces per box
The weight, in ounces, of one box is 15 ounces
Answer:
4.5
Step-by-step explanation:
Here's what I found on google about distributive property:
To “distribute” means to divide something or give a share or part of something. According to the distributive property, multiplying the sum of two or more addends by a number will give the same result as multiplying each addend individually by the number and then adding the products together.
Now for the math-
distribute the numbers- 0.05(50)+0.05(40)
solve- 0.05*50= 2.5
0.05*40= 2
2.5+2= 4.5
Hope this helps
Answer: The total interest paid on the mortgage is $179550
Step-by-step explanation:
The initial cost of the property is $300000. If he deposits $30000, the remaining amount would be
300000 - 30000 = $270000
Since the remaining amount was compounded, we would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = 270000
r = 2% = 2/100 = 0.02
n = 12 because it was compounded 12 times in a year.
t = 25 years
Therefore,
A = 270000(1+0.02/12)^12 × 25
A = 270000(1+0.0017)^300
A = 270000(1.0017)^300
A = $449550
The total interest paid on the mortgage is
449550 - 270000 = $179550
Answer:
WV is the perpendicular bisector of UT.
Answer:
The answer is option 2
Step-by-step explanation:
Working out above
