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melomori [17]
3 years ago
6

What is the product of(-1/4)x(-3/7)?write your answer in the simplest fraction form.

Mathematics
1 answer:
Murrr4er [49]3 years ago
8 0
Is the 'x' a variable or multiplication ???
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Help
aniked [119]

Answer:

39.3%

Step-by-step explanation:

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3 years ago
Solve 1 And 2 Step Equations.
masha68 [24]

Answer:

ksbdksvudkdbckx skxid SORRRYYYYY BUT I NEED POINTSSSSS :(

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A hypothetical square grows so that the length of its diagonals are increasing at a rate of 8m/min. How fast is the area of the
ad-work [718]

Answer: The area of the square is increasing at a rate of 90.4 m2/min (square meters/minute)

Step-by-step explanation: Please see the attachments below

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3 years ago
Read 2 more answers
Use the ladder method to find the factored version of this expression. (3x-18)
Vera_Pavlovna [14]

Answer:

-51

Step-by-step explanation:

cheggs acc

6 0
3 years ago
83 random samples were selected from a normally distributed population and were found to have a mean of 32.1 and a standard devi
arlik [135]

Answer:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.525 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.127 \leq \sigma \leq 2.757

Step-by-step explanation:

Information given

\bar X=32.1 represent the sample mean

\mu population mean (variable of interest)

s=2.4 represent the sample standard deviation

n=83 represent the sample size  

Confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom given by:

df=n-1=8-1=7

The confidence level is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,82)" "=CHISQ.INV(0.95,82)". so for this case the critical values are:

\chi^2_{\alpha/2}=104.139

\chi^2_{1- \alpha/2}=62.132

The confidence interval is given by:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.525 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.127 \leq \sigma \leq 2.757

5 0
3 years ago
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