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Murljashka [212]
3 years ago
8

What is the greatest value in the range of f(x)=x^2-5 for the domain {-5, -3, 0, 1, 2}?

Mathematics
1 answer:
kati45 [8]3 years ago
3 0
f(x)=x^2-5;\ x\in\{-5;-3;\ 0;\ 1;\ 2\}\\\\f(-5)=(-5)^2-5=25-5=20\\f(-3)=(-3)^2-5=9-5=4\\f(0)=0^2-5=-5\\f(1)=1^2-5=1-5=-4\\f(2)=2^2-5=4-5=-1\\\\Answer:f(-5)=20
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