3 years ago

What is the greatest value in the range of f(x)=x^2-5 for the domain {-5, -3, 0, 1, 2}?

1 answer:

3 0

$f(x)=x^2-5;\ x\in\{-5;-3;\ 0;\ 1;\ 2\}\\\\f(-5)=(-5)^2-5=25-5=20\\f(-3)=(-3)^2-5=9-5=4\\f(0)=0^2-5=-5\\f(1)=1^2-5=1-5=-4\\f(2)=2^2-5=4-5=-1\\\\Answer:f(-5)=20$

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