What is the greatest value in the range of f(x)=x^2-5 for the domain {-5, -3, 0, 1, 2}?

1 answer:

3 0

$f(x)=x^2-5;\ x\in\{-5;-3;\ 0;\ 1;\ 2\}\\\\f(-5)=(-5)^2-5=25-5=20\\f(-3)=(-3)^2-5=9-5=4\\f(0)=0^2-5=-5\\f(1)=1^2-5=1-5=-4\\f(2)=2^2-5=4-5=-1\\\\Answer:f(-5)=20$

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Step-by-step explanation:

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Answer:

C. (9, 18)

Step-by-step explanation:

Given R(3, 5), a dilation by a factor of 3 will multiply each coordinate to give ...

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<em>Comment on multiple choice answers</em>

As it often does, here it works to "guess" the answer that has the coordinates that are most-repeated. An x-coordinate of 9 is part of 3 answer choices; a y-coordinate of 18 is the only repeated value in the answer choices. If you were to guess, an appropriate guess would be (9, 18). That happens to be correct in this case.

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3 years ago

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Answer:

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