Answer:
Step-by-step explanation:
The complete question is:
<em>A sequence is defined recursively using the equation f(n + 1) = f(n) – 8. If f(1) = 100, what is f(6) ?</em>
Since, A sequence is defined recursively using the equation f(n + 1) = f(n) – 8. If f(1) = 100,we have to find the value of f(6).
Consider
f(n+1) = f(n)-8
Let n =1, we get
f(1+1) = f(2) = f(1) - 8 = 100-8 = 92
Let n =2, we get
f(2+1) = f(3) = f(2) - 8 = 92-8 = 84
Let n =3, we get
f(3+1) = f(4) = f(3)-8 = 84 - 8 = 76
Let n =4, we get
f(4+1) = f(5) = f(4)-8 = 76 - 8 = 68
Let n =5, we get
f(5+1) = f(6) = f(5) - 8 = 68-8 = 60
Therefore, the value of f(6) is 60.
