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3 years ago

What is 1/2+1/3+1/6+1/2+1/8+1/4

Mathematics

2 answers:

Harrizon [31]3 years ago

4 0

The answer is 90/80 which can be simplified to 1 42/48 or 1 21/24

ale4655 [162]3 years ago

3 0

Answer:

1 7/8

Step-by-step explanation:

1/2 + 1/3 + 1/6 + 1/2 + 1/8 + 1/4

convert to the common denominator, which is 24

12/24 + 8/24 + 4/24 + 12/24 + 3/24 + 6/24

simplify

1 21/24

reduce (divide the numerator and the denominator by 3)

1 7/8

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HELP BRAINLIEST FOR CORRECT ANSWER

Bad White [126]

Answer:

green: y= 1x+4

yellow: undefined x=1

blue: y= 2/-1x + 4

black: y= 0+-6

Step-by-step explanation:

ausuming u need slope intercept form

8 0

3 years ago

What will be the result of substituting 2 for x in both expressions below? One-half x + 4 x + 6 minus one-half x minus 2 Both ex

tiny-mole [99]

Replace x with 2 and solve each equation:

1/2(2) + 4 = 1 + 4 = 5

2+ 6 -1/2(2) -2 = 8-3 = 5

The answer is:

both expressions equal 5 when substituting 2 for x because the expressions are equivalent.

7 0

2 years ago

The diameter of a circle is 14 inches. Find the circumstance and area use 22/7

s344n2d4d5 [400]

Answer:

Circumference= 44 in

Area= 154 in²

Step-by-step explanation:

$\boxed{circumference \: of \: circle = 2\pi r}$

Radius

= diameter ÷2

= 14 ÷2

= 7 in

Circumference of circle

$= 2( \frac{22}{7} )(7)$

= 44 in

$\boxed{area \: of \: circle = \pi {r}^{2} }$

Area of circle

$= \frac{22}{7} ( {7}^{2} )$

= 154 in²

3 0

3 years ago

It takes Jack Frost 5 minutes to fly 35 minutes with the wind. It takes him 7 minutes to go 35 minutes against the wind. Determi

dezoksy [38]

Answer:his speed in still air is 6 miles per minute.

the speed of the wind is 1 mile per minute.

Step-by-step explanation:

Let x represent his speed in still air.

Let y represent the speed of the wind.

It takes Jack Frost 5 minutes to fly 35 miles with the wind. This means that his total speed would be x + y

Distance = speed × time

It means that

35 = 5(x + y)

35 = 5x + 5y - - - - - - - - - - -1

It takes him 7 minutes to go 35 miles against the wind. This means that his total speed would be x - y

It means that

35 = 7(x - y)

35 = 7x - 7y - - - - - - - - - - -2

Multiplying equation 1 by 7 and equation 2 by 5, it becomes

245 = 35x + 35y

175 = 35x - 35y

Adding both equations, it becomes

420 = 70x

x = 420/70 = 6

Substituting x = 6 into equation 1, it becomes

35 = 5 × 6 + 5y

35 = 30 + 5y

5y = 35 - 30 = 5

y = 5/5 = 1

5 0

3 years ago

Lim (n/3n-1)^(n-1) n → ∞

n200080 [17]

Looks like the given limit is

$\displaystyle \lim_{n\to\infty} \left(\frac n{3n-1}\right)^{n-1}$

With some simple algebra, we can rewrite

$\dfrac n{3n-1} = \dfrac13 \cdot \dfrac n{n-9} = \dfrac13 \cdot \dfrac{(n-9)+9}{n-9} = \dfrac13 \cdot \left(1 + \dfrac9{n-9}\right)$

then distribute the limit over the product,

$\displaystyle \lim_{n\to\infty} \left(\frac n{3n-1}\right)^{n-1} = \lim_{n\to\infty}\left(\dfrac13\right)^{n-1} \cdot \lim_{n\to\infty}\left(1+\dfrac9{n-9}\right)^{n-1}$

The first limit is 0, since 1/3ⁿ is a positive, decreasing sequence. But before claiming the overall limit is also 0, we need to show that the second limit is also finite.

For the second limit, recall the definition of the constant, e :

$\displaystyle e = \lim_{n\to\infty} \left(1+\frac1n\right)^n$

To make our limit resemble this one more closely, make a substitution; replace 9/(n - 9) with 1/m, so that

$\dfrac{9}{n-9} = \dfrac1m \implies 9m = n-9 \implies 9m+8 = n-1$

From the relation 9m = n - 9, we see that m also approaches infinity as n approaches infinity. So, the second limit is rewritten as

$\displaystyle\lim_{n\to\infty}\left(1+\dfrac9{n-9}\right)^{n-1} = \lim_{m\to\infty}\left(1+\dfrac1m\right)^{9m+8}$

Now we apply some more properties of multiplication and limits:

$\displaystyle \lim_{m\to\infty}\left(1+\dfrac1m\right)^{9m+8} = \lim_{m\to\infty}\left(1+\dfrac1m\right)^{9m} \cdot \lim_{m\to\infty}\left(1+\dfrac1m\right)^8 \\\\ = \lim_{m\to\infty}\left(\left(1+\dfrac1m\right)^m\right)^9 \cdot \left(\lim_{m\to\infty}\left(1+\dfrac1m\right)\right)^8 \\\\ = \left(\lim_{m\to\infty}\left(1+\dfrac1m\right)^m\right)^9 \cdot \left(\lim_{m\to\infty}\left(1+\dfrac1m\right)\right)^8 \\\\ = e^9 \cdot 1^8 = e^9$

So, the overall limit is indeed 0:

$\displaystyle \lim_{n\to\infty} \left(\frac n{3n-1}\right)^{n-1} = \underbrace{\lim_{n\to\infty}\left(\dfrac13\right)^{n-1}}_0 \cdot \underbrace{\lim_{n\to\infty}\left(1+\dfrac9{n-9}\right)^{n-1}}_{e^9} = \boxed{0}$

7 0

3 years ago