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3 years ago

Lines L and M are parallel find m parallel to 5

Mathematics

2 answers:

Illusion [34]3 years ago

5 0

You are given an angle of 38 degrees, which is a supplementary angle to angle 7.

Angle 7 = 180 - 38 = 142 degrees.

Angle 7 and angle 5 are Corresponding angles, which means they are equal.

Angle 5 = angle 7 = 142 degrees.

Nookie1986 [14]3 years ago

4 0

Answer:

142° = m parallel to 5

Step-by-step explanation:

The angle 7 is equal to the angle 5 in measure, since L and M are parallel lines.

When calculating the value of angle 7 we will find m parallel to 5.

The bottom of the line M forms an angle of 180°, so

180° = Angle 7 + 38°, and isolating Angle 7, we have

Angle 7 = 180° - 38°

Angle 7 = 142°, then

Angle 7 = Angle 5 = 142° = m parallel to 5

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The 18 faculty members in a college math department range in age from 32 to 68. A stem plot follows: The first and third quartil

valentina_108 [34]

Answer:

$Q_{1}=39, \:and\: Q_{3}=58$

Step-by-step explanation:

1) This Stem and Leaf plot works like a Histogram. Completing the question, check below the Stem plot. Look the data out of the Stem plot and within (in the graph below)

32, 34 , 38 , 39 , 39 , 40 , 43 , 45 , 46 , 49 , 53 , 54 , 57 , 58 , 59 , 59 , 63 , 68

2) Notice how the first digit is on the Stem column (check below)

3) To find the first and Third Quartiles

Let's use the formulas to find the position, then the value. As it follows:

$Q_3=\frac{3}{4}(n+1) \Rightarrow Q_3=\frac{3}{4}(18+1) Q_3=14.25 \approx14th =58$

$Q_1=\frac{(n+1)}{4} \Rightarrow Q_1=4.75 th \approx Q_1 =5th =39$

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3 years ago

The box plot below shows the total amount of time, in minutes, the students of a class surf the Internet every day:

inn [45]

A: highest and lowest time surfing the internet
What the look at on the internet
B: 40 to 60 minutes
It represents the middle half of the students in the class
C: there should be no significant effect on the interquartile range if there is an outlier. The graph as a whole would have longer “whiskers” though.

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3 years ago

Please help! And explain the answers too!

RideAnS [48]

1) He worked 4 hours leaving 6 more hours for him.
rate for A alone 6 baker
rate for A & B together 4
1/a+1/b=1/x
1/6+1/b=1/4
1/b=1/4-1/6
1/b=6/24-4/24
1/b=2/24
1/b=1/12
b=12
rate for wife alone 12 hours for the remaining 6 hours
check
1/6+1/12=1/4
12/72+6/72=1/4
18/72=1/4
ok
codewa
But we want to know how long it would have taken her for the whole job not just part of it
he works twice as fast as she does so the job that takes him 10 hours alone would take her 20 hours alone.

2) jessica and cynthia work in a pet shop.
it takes jessica 6 hours to groom all the pets but cynthia needs 8 hours to groom them.
if jessica starts to groom 1 hour before cynthia joins, how long will it take them to finish?
:
let t = time it takes them to finish (C's working time)
then
t+1 = J's working time
let 1 = completed job (all pets groomed)
:
A shared work equation, each does a fraction of the job, the two fractions add up to 1
%28%28t%2B1%29%29%2F6 + t%2F8 = 1
Multiply by the least common multiple of 6 and 8, 24. cancel the denominators
4(t+1) + 3t = 24
4t + 4 + 3t = 24
4t + 3t = 24 - 4
7t = 20
t = 20/7
t = 26%2F7 hrs, which is: 2 + 6%2F7*60 = 2 hrs 51.43 min to finish the job

3) math club takes 40 minutes
science takes 50 minutes.
rate * time = quantity
quantity = 1 set up of the tables.
rate for math club is 1/40 of all the tables in 1 minute.
rate for science club is 1/50 of all the tables in 1 minute.
math club works for 10 minutes.
rate * time = quantity
1/40 * 10 = 10/40 = 1/4 of the tables are already set up by the math club.
there are 3/4 of the tables that still need to be set up.
rate * time = quantity
the rates of the math club and the science club are additive.
(1/40 + 1/50) * time = 3/4 of the tables that still need to be set up.
common denominator is 200.
(5/200 + 4/200) * time = 3/4.
9/200 * time = 3/4
time = 3/4 * 200/9 = 600 / 36 = 16 and 2/3 minutes.
total time required is 10 + 16 + 2/3 minutes = 26 + 2/3 minutes.
how to check.
10 minutes is used to do 1/4 of the tables.
16 + 2/3 minutes is used to do the remaining 3/4 of the tables.
combined rate of math and science club is 9/200 of the tables in 1 minute.
math club rate of 1/40 * 10 = 10/40 = 1/4 of the tables.
combine rate of 9/200 * (16 + 2/3) = 9/200 * 50/3 = 450/600 = 9/12 = 3/4 of the tables.
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Drupady [299]

Answer:

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Step-by-step explanation:

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3 years ago

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IrinaVladis [17]

What following function tool?

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3 years ago