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NISA [10]
3 years ago
7

Find the area of each composite figure. Show ALL formulas required to solve and label the answer.

Mathematics
2 answers:
mafiozo [28]3 years ago
6 0
The one on the left is 6 (1/2x3x4) and the one on the right is 72 (6x12)
Semenov [28]3 years ago
5 0

Answer:

6 (1/2x3x4) and the one on the right is 72 (6x12)

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2x + 25x9 +3<br> What would x be for it to be equal
andrey2020 [161]

Answer:

X=144

Step-by-step explanation:

2X+25×9+3=0

2X+288

2X= -288

X= -144

8 0
2 years ago
The equation x 2 + 10 x + 25 = 0 has one solution.
Natalija [7]

Answer:

Yes

Step-by-step explanation:

X2+10x+25=0

So let's solve

10=5,5

25=5,5

So let's continue

X2+5x+5x+25

Let's factorise

X(x+5)+5(x+5)=0

(X+5)(x+5)=0

So

X+5=0

Substrate 5 from both sides

X=-5(twice)

So the answer is yes

4 0
3 years ago
How are piecewise functions and infinite limits alike? How are they different?
Shtirlitz [24]

Answer: i got 100% on the journal activity on EDGE with this “ The difference of piecewise functions and infinite limits is the graphs, with piecewise functions you're graphing several equations... when looking at a graph with an infinite limit there is a difference. A similarity they do have is their end points.” I haven’t been paying attention at all so this I made this up and some how it works(?!)

Step-by-step explanation: I’m not sure if it’s even correct but it worked as a response!

3 0
3 years ago
The rate (in liters per minute) at which water drains from a tank is recorded at half-minute intervals. Use the average of the l
kvv77 [185]

Answer:

100.75 liters

Step-by-step explanation:

Data provided in the question:

t (min)     0     0.5      1     1.5      2      2.5      3

r (l/min)    44    40     37     34     30     27      23

Now,

left endpoint approximation

= 0.5 × ( 44 + 40 + 37 + 34 + 30 + 27 )

= 0.5 × 212

= 106

Right endpoint approximation

= 0.5 × ( 40 + 37 + 34 + 30 + 27 + 23 )

= 0.5 × 191

= 95.5

Therefore,

the average of the left- and right-endpoint approximations

= [ 106 + 95.5 ] ÷ 2

= 100.75 liters

3 0
3 years ago
Paulo ran a marathon in about 1.56 x 10^4 s. Write Paulo’s time in standard notation. Miguel ran a marathon in 4 h and 16 min. W
nikdorinn [45]
Paulo ran a marathon in about 4 1.56 10 s. 
(a) Write Paulo’s time in standard notation.
(b) Miguel ran a marathon in 4 h and 16 min. Who ran the race in the shorter amount of time? Show your
7 0
3 years ago
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