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3 years ago

Help me please . I am stuck

Mathematics

1 answer:

Radda [10]3 years ago

7 0

Answer: n⁴+10n²x+25x²

Step-by-step explanation:

I don;t know how I can use the binomial squares pattern on Brainly, but I can definitely guide you through the problem.

(n²+5x)² [rewrite this from the squared]

(n²+5x)(n²+5x) [use FOIL to expand]

n⁴+5n²x+5n²x+25x² [combine like terms]

n⁴+10n²x+25x²

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Would it still be 3.19? Because you don't need to round to 3.20 because 3.192 <--- the 2 won't do anything.. If it's 5 or hig

Leviafan [203]

Yes, remember this 4 or less let it rest, 5 or more let it soar.

7 0

3 years ago

The length of the base of a rectangular prism is given as x + 4, and the width of the base is x +2. The height of the rectangula

lutik1710 [3]

Answer:

V(x) = (x +4)(x +2)(2x +11)

Step-by-step explanation:

For length L = (x+4), the height is ...

2L +3 = 2(x+4) +3

= 2x +8 +3

= 2x +11

The volume is the product of length, width, and height, so is ...

V = (x +4)(x +2)(2x +11)

8 0

3 years ago

Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

7 0

3 years ago

Pls helpppppp this stuff makes no sense

yulyashka [42]

Answer:

x = 5

Step-by-step explanation:

a || b and a line intersecting them is their transversal.

$\therefore m\angle 1=m\angle 5\\(corresponding \:\angle 's) \\\\\therefore 60 - 2x = 70 - 4x\\\\\therefore 4x - 2x = 70 - 60\\\\\therefore 2x = 10\\\\\therefore x =\frac{10}{2} \\\\\huge \orange {\boxed {\therefore x = 5}}$

4 0

3 years ago

Write each phrase as a variable expression:<br><br> 9 subtracted from x

Schach [20]

Answer:

9-x

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers