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Bogdan [553]
3 years ago
12

What single decimal multiplier would you use to increase by 15% followed by a 17% decrease?

Mathematics
2 answers:
zloy xaker [14]3 years ago
8 0

Answer:

1.3455

Step-by-step explanation:

A 15% increase is a multiplication by 1.15

So a 15% and a 17% increase is a multiplication of 1.15*1.17 = 1.3455

Karolina [17]3 years ago
7 0

Answer:

0.9545

Step-by-step explanation:

Let an integer be x.

If x is increased by 15%, then the value of the number would be

115/100x=1.15x

If 1.15x is decreased by 17%, then the value of the number would be:

(100-17)/100×1.15x

83/100×1.15x=0.9545x

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-16 is the answer :)
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375 ÷ 3 = n. what do you guys think it is answers?????
morpeh [17]

Answer:125=n

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A King in ancient times agreed to reward the inventor of chess with one grain of wheat on the first of the 64 squares of a chess
maxonik [38]

Answer:

Total weight of the wheat placed on 45th square will be = 1.26\times 10^{6}tons

Step-by-step explanation:

King rewarded the inventor of chess by giving grain of wheat on every square of the chess board. He places one  grain of wheat on first square, 2 on second, 4 on 3rd, 8 on 4th and so on.

In fact he places grains of wheat in a progression S = 1, 2, 4, 8, 16.........n terms where value of n is 64.

We can rewrite the progression as S = 2°, 2, 2², 2³,.........n terms (n = 64)

In a geometric progression we know the nth term = a(r^{n-1})

where a = first term of the series, r = common ratio, n = number of terms

Now we have to calculate the weight of all wheat placed on 45th square.

So we will put the values in the given formula 45th term =

1\times (2^{45-1}) = 2^{44}=1.76\times 10^{13}

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7 0
3 years ago
Determine the rational zeros for the function f(x)=x^3+7x^2+7x-15
alexandr402 [8]

Answer:

1,-3,-5

Step-by-step explanation:

Given:

f(x)=x^3+7x^2+7x-15

Finding all the possible rational zeros of f(x)

p= ±1,±3,±5,±15 (factors of coefficient of last term)

q=±1(factors of coefficient of leading term)

p/q=±1,±3,±5,±15

Now finding the rational zeros using rational root theorem

f(p/q)

f(1)=1+7+7-15

   =0

f(-1)= -1 +7-7-15

     = -16

f(3)=27+7(9)+21-15

    =96

f(-3)= (-3)^3+7(-3)^2+7(-3)-15

     = 0

f(5)=5^3+7(5)^2+7(5)-15

    =320

f(-5)=(-5)^3+7(-5)^2+7(-5)-15

      =0    

f(15)=(15)^3+7(15)^2+7(15)-15

     =5040

f(-15)=(-15)^3+7(-15)^2+7(-15)-15

      =-1920

Hence the rational roots are 1,-3,-5 !

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27 + x is the simplified expression.
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