2 years ago

PLEASE HELP! 15 points i need help plz look at picture

Mathematics

2 answers:

nasty-shy [4]2 years ago

6 0

Answer:

Step-by-step explanation:

hope this helps not sure if right though hard to see picture is blurry when I zoom in

Elena-2011 [213]2 years ago

5 0

14

hope this helps have a good day

You might be interested in

Please help solve for angles Q X and Z

Iteru [2.4K]

Answer:

125

Step-by-step explanation:

Sum of Exterior Angles must add to 360 so

$60 + 70 + 40 + 65 + x = 360$

$235 + x = 360$

$x = 125$

6 0

3 years ago

Y+3 1/2=6 help pleaseee

Verdich [7]

3 1/2 = 7/2
so y+7/2 = 6
y=6-7/2 = 12-7 / 2 = 5/2 = 2 1/2

8 0

2 years ago

Simplify 5x^2y(4x^3-3y^2)-2yx^3(4x^2-2x)+6

sladkih [1.3K]

The simplified version of this equation is

8 0

2 years ago

during spring break an amusement park had 359,479 visitors and a water park had 325,737 visitors. The zoo had more visitors than

bonufazy [111]

359,479 - 325,737
=33742

3 0

2 years ago

The height h (in feet) of an object t seconds after it is dropped can be modeled by the quadratic equation h = -16t2 + h0, where

Reil [10]

Answer:

The rock will reach to the canyon floor in 3.99 seconds.

Step-by-step explanation:

The height h (in feet) of an object t seconds after it is dropped can be modeled by the quadratic equation

$h=-16t^2+255$

Where, h0 is the initial height of the object.

It can be written as

$h=-16t^2+0t+255$

The height of the object is zero if it will reach to the canyon floor.

$0=-16t^2+0t+255$

Quadratic formula:

$t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here a=-16, b=0 and c=255.

$t=\frac{-0\pm \sqrt{0^2-4(-16)(255)}}{2(-16)}$

$t=\frac{\pm \sqrt{16320}}{-32}$

$t=\pm 3.99$

Time cannot be negative, therefore the rock will reach to the canyon floor in 3.99 seconds.

3 0

3 years ago

Read 2 more answers