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Ivan
2 years ago
6

PLEASE HELP! 15 points i need help plz look at picture

Mathematics
2 answers:
nasty-shy [4]2 years ago
6 0

Answer:

14

Step-by-step explanation:

hope this helps not sure if right though hard to see picture is blurry when I zoom in

Elena-2011 [213]2 years ago
5 0
14

hope this helps have a good day
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Step-by-step explanation:

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2 years ago
The height h (in feet) of an object t seconds after it is dropped can be modeled by the quadratic equation h = -16t2 + h0, where
Reil [10]

Answer:

The rock will reach to the canyon floor in 3.99 seconds.

Step-by-step explanation:

The height h (in feet) of an object t seconds after it is dropped can be modeled by the quadratic equation

h=-16t^2+255

Where, h0 is the initial height of the object.

It can be written as

h=-16t^2+0t+255

The height of the object is zero if it will reach to the canyon floor.

0=-16t^2+0t+255

Quadratic formula:

t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Here a=-16, b=0 and c=255.

t=\frac{-0\pm \sqrt{0^2-4(-16)(255)}}{2(-16)}

t=\frac{\pm \sqrt{16320}}{-32}

t=\pm 3.99

Time cannot be negative, therefore the rock will reach to the canyon floor in 3.99 seconds.

3 0
3 years ago
Read 2 more answers
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