We will use the following law of indices (or 'index law') to check each pair of expression
![x^{ \frac{m}{n}} = ( \sqrt[n]{x} )^{m}](https://tex.z-dn.net/?f=%20x%5E%7B%20%5Cfrac%7Bm%7D%7Bn%7D%7D%20%3D%20%28%20%5Csqrt%5Bn%5D%7Bx%7D%20%29%5E%7Bm%7D%20)
With fractional power, the denominator is the root and the numerator is the power of the term. When the denominator is 2, we usually only write the normal square symbol (√). Denominator other than 2, we usually write the value of the root, for example, the cubic root ∛
Option A - Incorrect
should equal to
![( \sqrt[7]{7} )^{5}](https://tex.z-dn.net/?f=%20%28%20%5Csqrt%5B7%5D%7B7%7D%20%29%5E%7B5%7D%20)
Option B - Correct
does equal to
Option C - Incorrect
should equal to
Option D - Incorrect
should equal to
![( \sqrt[3]{5} )^{2}](https://tex.z-dn.net/?f=%20%28%20%5Csqrt%5B3%5D%7B5%7D%20%29%5E%7B2%7D%20)
Answer:
31.5 i think
Step-by-step explanation:i used multi if its wrong im so sorry
$37.95 x12= 455.4 so Kevin’s cellphone will cost 455.4 for the year
Answer:
0.6603 = 66.03% probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Sent by ABC Speedy Delivery Service.
Event B: Arrived on time.
The probability that any given parcel will be sent by the ABC Speedy Delivery Service is 0.71.
This means that 
The probability that the parcel will arrive on time given the ABC Speedy Delivery Company was used is 0.93.
This means that 
Find the probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.
This is . So
0.6603 = 66.03% probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.
A is the point (-4, 1)
i) reflection over the y-axis projects a point (a, b) to (-a, b):
(-4, 1) is projected to (4, 1),
ii) reflection over the x axis projects a point (a, b) to (a, -b):
(4, 1) is projected to (4, -1),
iii) rotation 180 degrees: projects (a, b) to (-a, -b):
so (4, -1) is projected to (-4, 1)
Answer: A'(-4, 1)
