6 * 2.5 = 15 That’s the area of the base
2.5 * 4 = 10
10 * 2 = 20
That’s the area of the 2 smaller sides
6 * 4 = 24
24 * 2 = 48
That’s the area of the 2 larger sides
Then you add all the dimensions together.
15+20+48 = 83.
So, the final equation is (6*2.5) + 2(2.5*4) + 2(6*4) = 83
3x + 9 + 3x =15
6x + 9 = 15
- 9 = -9
6x = 6
/6 /6
X =1
Answer:
Step-by-step explanation:
What this question is asking of you is what is the greatest common divisor of 12 and 15. Or, what is the biggest number that divides both 12 and 15.
in order to find this we have to split each number into it's prime components.
for 12 they are 2,2 and 3 (
2
⋅
2
⋅
3
=
12
)
and for 15 they are 3 and 5 (
3
⋅
5
=
15
)
Out of those two groups (2,2,3) and (3,5) the only thing in common is 3, so 3 is the greatest common divisor. That tells us that the greatest number of groups that can exist and have the same number of girls and the same number of boys for each group is 3.
Now to find out how many girls and boys there are going to be in each group we divide the totals by 3, so:
12
3
=
4
girls per group, and
15
3
=
5
boys per group.
(just as a thought exercise, if there were 16 boys, the divisors would have been (2,2,3) and (2,2,2,2), leaving us with 4 groups [
2
⋅
2
] of 3 girls [12/4] and 4 boys [16/4] )
Answer:
14.67 gram
Step-by-step explanation:
Henry has two pixie sticks full of delicious sugar.
Now, each pixie stick contains 22 grams of sugary goodness, then in two sticks, there will be (22 × 2) = 44 grams of sugar.
Now, Henry shares two pixie sticks among two friends and himself in equal proportion.
Therefore, each of his friends will get 
(Round to the nearest tenth) gram of sugary goodness. (Answer)
Answer: The proof is mentioned below.
Step-by-step explanation:
Here, Δ ABC is isosceles triangle.
Therefore, AB = BC
Prove: Δ ABO ≅ Δ ACO
In Δ ABO and Δ ACO,
∠ BAO ≅ ∠ CAO ( AO bisects ∠ BAC )
∠ AOB ≅ ∠ AOC ( AO is perpendicular to BC )
BO ≅ OC ( O is the mid point of BC)
Thus, By ASA postulate of congruence,
Δ ABO ≅ Δ ACO
Therefore, By CPCTC,
∠B ≅ ∠ C
Where ∠ B and ∠ C are the base angles of Δ ABC.
