Ask question

Ask question

All categories

3 years ago

8

Lynn is selling tickets. Student tickets cost $4 and adult tickets cost $6. She sells 525 tickets and collects $2876. How many o

f each ticket did she sell?

1 answer:

olganol [36]3 years ago

3 0

Answer:

44335%%÷<34÷×÷/44=

4433455

Step-by-step explanation:

ddeyu yet re 23<3÷>÷=tr d Tr RT6t33/×=+2××××××3

+÷+××÷1234×÷

133333445÷××312÷×2×

12443÷2÷

You might be interested in

A boat has two sails in the shape of right triangles, labeled A and B in the figure below.

Maru [420]

Answer:

The area of sail A is One-fourth the area of sail B.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

PLZ HELP TEST IS BEING TIMED!!! What are the slope and the y-intercept of the linear function that is represented by the equatio

Oksana_A [137]

Answer:

The slope is -10, and the y-intercept is 1

Step-by-step explanation:

The slope is in the equation and always has a variable next to it (In this case, -10x, so -10 is the slope)

The y-intercept is 1 and that is also in the equation and does not have any variables next to it (In this case, + 1, so it is 1)

3 0

3 years ago

Read 2 more answers

Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a

Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ( $\vec F$ ), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

$\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)$ (1)

Vector (ordered pair - polar form)

$\vec F = \left(\|\vec F\|, \theta\right)$

Sum of vectorial components (linear combination)

$\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}$ (2)

Where:

$\|\vec F\|$ - Norm of the vector force, in newtons.

$\theta$ - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

$\hat{i}$ , $\hat{j}$ - Orthogonal axes, no unit.

If we know that $\|\vec F\| = 30\,lbf$ and $\theta = 25^{\circ}$ , then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

$\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]$

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]$

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

8 0

2 years ago

Thepotemich [5.8K]

Answer:

20

Step-by-step explanation: -13 to 7 think about that. We have to add 13 to make it 0. Then we add 7. So 13 plus 7 is 20. Enjoy :)

4 0

3 years ago

Rochelle works part-time at the college museum, which pays her at a rate of $10 per hour. She also makes small bracelets that sh

katrin [286]

We know for our problem that Rachel makes $10 per hour. Since $x$ represent the number of hours that she works, $10x$ will be the total amount that she will make for working $x$ hours. We also know that she sells bracelets for $5 each. Since $y$ represents the number of of bracelets that she sells, $5y$ will be her total revenue for selling $y$ bracelets. We also know that she needs to earn at least $200 a week to cover her expenses, so the sum of $10x$ and $5y$ must be equal or greater than 200:

$10x+5 \geq 200$

We can conclude that <span>the graphs that shows the inequality that represents this situation, with its solution region shaded is:</span>

4 0

3 years ago