Answer:
A) f^-1(x)=(x-8)^3+2
Step-by-step explanation:
To find the function inverse, switch the x with y and solve for y.
![y=\sqrt[3]{x-2}+8 \\\\x=\sqrt[3]{y-2}+8\\\\(x-8)^3 = y-2\\\\ (x-8)^3 + 2 = y](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7Bx-2%7D%2B8%20%5C%5C%5C%5Cx%3D%5Csqrt%5B3%5D%7By-2%7D%2B8%5C%5C%5C%5C%28x-8%29%5E3%20%3D%20y-2%5C%5C%5C%5C%20%28x-8%29%5E3%20%2B%202%20%3D%20y)
Answer:
One possibility is that;
g(x) = (x + 1)
while h(x) = 5x^3
Step-by-step explanation:
Here, we are told to find one possibility for f(x) and g(x)
The term h(x) = (Fog)(x) means that we are inserting g(x) into f(x) to give h(x)
Now let’s have it this way;
We can see that g(x) = (x + 1) , then h(x) = 5x^3
This is one possibility of the values of g(x) and h(x)
A negative number is not considered a whole number...so ur answer is -229