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choli [55]
3 years ago
6

Explain your answer, please

Mathematics
2 answers:
Molodets [167]3 years ago
8 0

.1.Scale Factor of Triangle STU to Triangle PQR= 1.5

2.Scale Factor of Trapezoid EFGH to Trapezoid JKLM =2

3. about 90 armadillo

1.Side ST: 15 ÷ Side PQ: 10 = 1.5

2.Side JM: 14 ÷Side EH: 7 = 2

3.843/7=120.428571429

843/4=210.75

210.75-120.428571429=90.321428571

This rounds to 90 armadillo

Hope this helps :3 ❤

dmitriy555 [2]3 years ago
7 0
Scale factor of triangle stu to triangle Stu is the answer to y’all question I’m sorry if this wrong this is my best answer
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Answer pleaseee...!!!
Korvikt [17]

Answer: 23

Step-by-step explanation:

6 0
3 years ago
Umm I don’t remember this please help. I will give correct answer brainliest
VikaD [51]

Answer:

Option D

Step-by-step explanation:

F=\frac{9}{5}C+32\\\\F-32=\frac{9}{5}C  \\\\5(F-32)=9C\\\\\frac{5(F-32)}{9}=C  \\\\C=\frac{5}{9}( {F-32})

For F=77°F

C=\frac{5}{9}(F-32) \\\\C=\frac{5}{9}(77-32)\\\\C=\frac{5}{9}(45)\\\\C=\frac{225}{9} \\\\C=25

7 0
3 years ago
Use technology and the given confidence level and sample data to find the confidence interval for the population mean mu . assum
attashe74 [19]

To solve for the confidence interval for the population mean mu, we can use the formula:

Confidence interval = x ± z * s / sqrt (n)

where x is the sample mean, s is the standard deviation, and n is the sample size

 

At 95% confidence level, the value of z is equivalent to:

z = 1.96

 

Therefore substituting the given values into the equation:

Confidence interval = 3 ± 1.96 * 5.8 / sqrt (51)

Confidence interval = 3 ± 1.59

Confidence interval = 1.41, 4.59

 

Therefore the population mean mu has an approximate range or confidence interval from 1.41 kg to 4.59 kg.

6 0
3 years ago
LOOK AT PICTURE. VOLUME OF CAN PROBLEM
adoni [48]

Answer:

The correct answer is third option.  994

Step-by-step explanation:

<u>Points to remember</u>

Volume of cylinder = πr²h

Where 'r' is the radius and 'h' is the height of cylinder

From the given question we get the cylinder height and radius

The height h = 3 times the diameter of one ball

 = 3 * 7.5 = 22.5 cm

Radius = half of the diameter of a ball

 = 7.5/2 = 3.75 cm

<u>To find the volume of cylinder</u>

Volume of cylinder = πr²h

 = 3.14 * 3.75² * 22.5

 = 993.515 ≈ 994

The correct answer is third option.  994

8 0
3 years ago
Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

5 0
3 years ago
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