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Elanso [62]
3 years ago
15

Help me with this question

Mathematics
2 answers:
Viktor [21]3 years ago
8 0
He has 15 orange. 2 for 3 out of 25
Aleonysh [2.5K]3 years ago
4 0
He has 15 orange picks
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(4) |-5 + (-2)| _____ |5 + 2| <br> &lt;<br> &gt;<br> =
nikitadnepr [17]

Hi

The answer would be =

Why?

The `| |` symbols mean actual value, which makes every number inside of it positive. That would mean, following the rules of actual value, the equation would look like:

5 + 2 _____ 5 + 2

Both add up to 10, so both equations are equal.

4 0
3 years ago
Read 2 more answers
I don’t get this pls helppppppp!!!!!!!!!!!!
MrRa [10]

Answer:

1) f(x)<x+4

f(x)>-x-3

f(x)<5

ANSWER: (-3,4)

2)2.5>0+2

2.5<0+3

2.5<0+5

ANSWER: (0,2.5)

<u>----------------------------</u>

HOPE IT HELPS

HAVE A GREAT DAY!!

8 0
3 years ago
lisa had 2/3 of a box of cookies .She wanted to share the box among 8of her friend .How much of a box of cookies would each frie
Artist 52 [7]

Answer:

Each friend would receive 1/12 cookies

3 0
3 years ago
The automatic opening device of a military cargo parachute has been designed to open when the parachute is 200 m above the groun
kirill115 [55]

Step-by-step answer:

Given:

mean, mu = 200 m

standard deviation, sigma = 30 m

sample size, N = 5

Maximum deviation for no damage, D = 100 m

Solution:

Z-score for maximum deviation

= (D-mu)/sigma

= (100-200)/30

= -10/3

From normal distribution tables, the probability of right tail with

Z= - 10/3

is 0.9995709, which represents the probability that the parachute will open at 100m or more.

Thus, by the multiplication rule, the probability that all five parachutes will ALL open at 100m or more is the product of the individual probabilities, i.e.

P(all five safe) = 0.9995709^5 = 0.9978565

So there is an approximately 1-0.9978565 = 0.214% probability that at least one of the five parachutes will open below 100m

6 0
4 years ago
The table shows
lina2011 [118]

Answer:

B, but I may be wrong.

Step-by-step explanation:

7 0
4 years ago
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