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4 years ago

FOR 80 POINTS!!!!!!!!! HELP WITH MATH QUESTION PLS, THERE IS PICTURE!!!!!!!!!!

Mathematics

2 answers:

Tems11 [23]4 years ago

8 0

Answer: [ 36 -18

-12 -15 ]

Step-by-step explanation:

Nimfa-mama [501]4 years ago

6 0

Answer:

x=1/9

Step-by-step explanation:

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Pls answer if i dont get good grades i wont be able to play soccer

Harrizon [31]

Answer:

It’s A you are correct kid

Step-by-step explanation:

3 0

3 years ago

What integer does the arrow indicate?

Vsevolod [243]

Answer:

-9

Step-by-step explanation:

Given

See attachment for number line

Required

What does the arrow integer

Represent the value of the arrow with x.

The arrow is on number -9.

This number is what the arrow represents.

Hence:

$x = -9$

8 0

3 years ago

A rocket is shot straight up into the air with an initial velocity of 500 ft per second and from a height of 20 feet above the g

iragen [17]

The height of the rocket above the ground after $t$ seconds is given by the equation : $H= -16t^2+Vt+h$ , where $V$ is the initial velocity and $h$ is the initial height.

Given that, $V= 500 ft/second$ and $h= 20 ft$

So, the equation will become: $H= -16t^2 +500t+20$

A) For finding the height of the rocket 3 seconds after the launch, we will plug $t=3$ into the above equation. So....

$H= -16(3)^2+500(3)+20\\ \\ H= -16(9)+1500+20\\ \\ H= -144+1500+20=1376$

So, the height of the rocket 3 seconds after the launch is 1376 feet.

B) When the rocket at a height of 400 feet, then we will plug $H= 400$

$400=-16t^2+500t+20\\ \\ 16t^2-500t-20+400=0\\ \\ 16t^2-500t+380=0\\ \\ 4(4t^2-125t+95)=0\\ \\ 4t^2-125t+95=0$

Using quadratic formula, we will get......

$t= \frac{-(-125)+/-\sqrt{(-125)^2-4(4)(95)}}{2(4)}\\ \\ t= \frac{125+/-\sqrt{14105}}{8}\\ \\ t= 30.4705... \\ and \\ t= 0.7794...$

So, after 0.7794...seconds and 30.4705...seconds the rocket is at a height of 400 feet above the ground.

C) The time duration that the rocket remains in the air means we need to find the time taken by the rocket to reach the ground. When it reaches the ground, then $H=0$ . So.....

$0=-16t^2+500t+20\\ \\ -4(4t^2-125t-5)=0\\ \\ 4t^2-125t-5=0$

Using quadratic formula, we will get.....

$t= \frac{-(-125)+/-\sqrt{(-125)^2-4(4)(-5)}}{2(4)}\\ \\ t= \frac{125+/-\sqrt{15705}}{8}\\ \\ t=31.2899...\\ and\\ t= -0.0399...$

(Negative value is ignored as time can't be in negative)

So, the rocket will remain in the air for 31.2899... seconds.

5 0

4 years ago

M+1= -2(n+6) what does m equal?

bixtya [17]

Answer:

m= -2n-13

Step-by-step explanation:

1. Subract 1 from both sides

m=-2(n+6)-1

2. Mulitply n+6 by -2

m=-2n-12-1

3. m=-2n-13

6 0

3 years ago

Read 2 more answers

A table of values of a linear function is shown below. Find the output when the input is n

lesya692 [45]

y = 6 - n

Step-by-step explanation:

Step 1 :

Given ,

input: 1, 2, 3, 4 ,5 Output: 5, 4, 3, 2, 1

Let y = m x + c be the linear function

Step 2 :

When we take the input as 1, the output is 5, and when input is 2 the output is 4

so we have x,y as (1,5) and (2,4)

Hence substituting this in the linear function we get,

5 = m (1) + c and 4 = m (2) + c

=> m + c = 5 and 2 m + c = 4

Step 3 :

Solving for m and c with these 2 equations , we have

m = -1 and c = 6

so we have the equation as y= (-1) x + 6

When the input is n, x = n

so output is y = (-1) n + 6

y = 6 - n

5 0

4 years ago